运行scrapy网络爬虫时出错答案

【问题标题】：Error while running scrapy web crawler运行scrapy网络爬虫时出错
【发布时间】：2014-07-01 04:08:32
【问题描述】：

import scrapy

class ExampleSpider(scrapy.Spider):
    name = "example"
    allowed_domains = ["dmoz.org"]
    start_urls = [
        "http://www.dmoz.org/Computers/Programming/Languages/Python/Books/",
        "http://www.dmoz.org/Computers/Programming/Languages/Python/Resources/"
    ]

    def parse(self, response):
        for sel in response.xpath('//ul/li'):
            title = sel.xpath('a/text()').extract()
            link = sel.xpath('a/@href').extract()
            desc = sel.xpath('text()').extract()
            print title, link, desc

但是，当我尝试调用蜘蛛时，我收到以下错误消息：

[example] ERROR: Spider error processing <GET http://www.dmoz.org/Computers/Programming/Languages/Python/Books/>
    Traceback (most recent call last):
      File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/twisted/internet/base.py", line 1178, in mainLoop
        self.runUntilCurrent()
      File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/twisted/internet/base.py", line 800, in runUntilCurrent
        call.func(*call.args, **call.kw)
      File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/twisted/internet/defer.py", line 368, in callback
        self._startRunCallbacks(result)
      File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/twisted/internet/defer.py", line 464, in _startRunCallbacks
        self._runCallbacks()
    --- <exception caught here> ---
      File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/twisted/internet/defer.py", line 551, in _runCallbacks
        current.result = callback(current.result, *args, **kw)
      File "/Users/andy2/Documents/Python/tutorial/tutorial/spiders/example.py", line 18, in parse
        print title, link, desc
    exceptions.NameError: global name 'link' is not defined

我可以做些什么来使这段代码正常工作吗？

谁能帮帮我？

谢谢！！！

【问题讨论】：

标签： python web-scraping scrapy scrapy-spider

【解决方案1】：

您需要实例化 Selector 并将 response 作为参数传递。此外，您的导入不正确。这是蜘蛛的固定版本：

from scrapy.selector import Selector
from scrapy.spider import Spider


class ExampleSpider(Spider):
    name = "example"
    allowed_domains = ["dmoz.org"]
    start_urls = [
        "http://www.dmoz.org/Computers/Programming/Languages/Python/Books/",
        "http://www.dmoz.org/Computers/Programming/Languages/Python/Resources/"
    ]

    def parse(self, response):
        sel = Selector(response)
        for li in sel.xpath('//ul/li'):
            title = li.xpath('a/text()').extract()
            link = li.xpath('a/@href').extract()
            desc = li.xpath('text()').extract()
            print title, link, desc

【讨论】：