按属性值对对象数组进行排序答案

【问题标题】：Sorting an array of objects by property values按属性值对对象数组进行排序
【发布时间】：2010-11-02 00:43:33
【问题描述】：

我使用 AJAX 获得了以下对象并将它们存储在一个数组中：

var homes = [
    {
        "h_id": "3",
        "city": "Dallas",
        "state": "TX",
        "zip": "75201",
        "price": "162500"
    }, {
        "h_id": "4",
        "city": "Bevery Hills",
        "state": "CA",
        "zip": "90210",
        "price": "319250"
    }, {
        "h_id": "5",
        "city": "New York",
        "state": "NY",
        "zip": "00010",
        "price": "962500"
    }
];

我如何创建一个函数，以仅使用 JavaScript 以升序或降序顺序通过 price 属性对对象进行排序？

【问题讨论】：

最快的方法是使用同构的sort-array 模块，它可以在浏览器和节点中本地工作，支持任何类型的输入、计算字段和自定义排序顺序。

标签： javascript arrays sorting

【解决方案1】：

 function compareValues(key, order = 'asc') {
  return function innerSort(a, b) {
    if (!a.hasOwnProperty(key) || !b.hasOwnProperty(key)) {
      // property doesn't exist on either object
      return 0;
    }

    const varA = (typeof a[key] === 'string')
      ? a[key].toUpperCase() : a[key];
    const varB = (typeof b[key] === 'string')
      ? b[key].toUpperCase() : b[key];

    let comparison = 0;
    if (varA > varB) {
      comparison = 1;
    } else if (varA < varB) {
      comparison = -1;
    }
    return (
      (order === 'desc') ? (comparison * -1) : comparison
    );
  };
}

http://yazilimsozluk.com/sort-array-in-javascript-by-asc-or-desc

【讨论】：

【解决方案2】：

如果您不想使用任何sort() 方法，可以使用以下方法

function sortObj(obj) {
  let numArr = []; //the array which just includes prices as Number
  let sortedObj = [];
  obj.map((x) => {
    numArr.push(Number(x["price"]));
  });

  while (numArr.length > 0) { 
    let minIndex = numArr.indexOf(Math.min(...numArr)); //the index of cheapest home in the obj
    numArr.splice(minIndex, 1); 
    sortedObj.push(obj.splice(minIndex, 1)); // splicing cheapest home from Homes Array to sortedObj Array.
  }

  console.log(sortedObj);
}

var homes = [
  {
    h_id: "3",
    city: "Dallas",
    state: "TX",
    zip: "75201",
    price: "162500",
  },
  {
    h_id: "4",
    city: "Bevery Hills",
    state: "CA",
    zip: "90210",
    price: "319250",
  },
  {
    h_id: "5",
    city: "New York",
    state: "NY",
    zip: "00010",
    price: "962500",
  },
];
sortObj(homes);

【讨论】：