【发布时间】:2021-05-13 16:40:18
【问题描述】:
我编写了一些代码来从https://www.horseracing.net/racecards 收集每个赛道的 URL。我还编写了一些代码来从每个赛道页面中抓取数据。
每一段代码都可以正常工作,但我无法创建一个 for 循环来遍历所有赛道 URL。
以下是抓取课程网址的代码:
import requests
from bs4 import BeautifulSoup
from urllib.parse import urljoin
todays_racecard_url = 'https://www.horseracing.net/racecards'
base_url = "https://www.horseracing.net"
reqs = requests.get(todays_racecard_url)
content = reqs.text
soup = BeautifulSoup(content, 'html.parser')
course_urls = []
for h in soup.findAll('h3'):
a = h.find('a')
try:
if 'href' in a.attrs:
card_url = urljoin(base_url, a.get('href'))
course_urls.append(card_url)
except:
pass
for card_url in course_urls:
print(card_url)
这是抓取页面的代码:
import requests
from requests import get
from bs4 import BeautifulSoup
import pandas as pd
import numpy as np
url = "https://www.horseracing.net/racecards/fontwell/13-05-21"
results = requests.get(url)
soup = BeautifulSoup(results.text, "html.parser")
date = []
course = []
time = []
runner = []
tips = []
tipsters = []
runner_div = soup.find_all('div', class_='row-cell-right')
for container in runner_div:
runner_name = container.h5.a.text
runner.append(runner_name)
tips_no = container.find('span', class_='tip-text number-tip').text if container.find('span', class_='tip-text number-tip') else ''
tips.append(tips_no)
tipster_names = container.find('span', class_='pointers-text currency-text').text if container.find('span', class_='pointers-text currency-text') else ''
tipsters.append(tipster_names)
newspaper_tips = pd.DataFrame({
'Runners': runner,
'Tips': tips,
'Tipsters': tipsters,
})
newspaper_tips['Tipsters'] = newspaper_tips['Tipsters'].str.replace(' - ', '')
newspaper_tips.to_csv('NewspaperTips.csv', mode='a', header=False, index=False)
我如何加入他们以获得我正在寻找的结果?
【问题讨论】:
-
将抓取页面的代码放在一个以url为参数的函数中。然后在初始脚本的最后一个循环中遍历它。
标签: python beautifulsoup