Selenium not .click 给出“对象不可调用”错误

Question

我正在尝试自动化我的租赁搜索。我可以获得结果的第一页，但是当我尝试单击下一个按钮时出现错误 - “对象不可调用”我是 Python 新手，只是认为这将是一个有趣的项目来学习 - 任何帮助。

from selenium import webdriver
from bs4 import BeautifulSoup
import datetime
from datetime import timedelta
import time
import re






pages = set()

def getLinks(url):
global pages
# Open web browser and get url - 3 second time delay.
driver = webdriver.Firefox()
driver.get(url)
time.sleep(3)
pageSource = driver.page_source
bsObj = BeautifulSoup(pageSource)
for addr_link in bsObj.findAll("a", href=re.compile("^/homedetails/*")):
    if 'href' in addr_link.attrs:
        if addr_link['href'] not in pages:
            newPage = addr_link.attrs['href']
            pages.add(newPage)
            print(newPage)

#if bsObj.find('li', {'class': "zsg-pagination-next"}) == True:
next_page = bsObj.find('li', {'class': "zsg-pagination-next"}).find("a")
#next_page.click()
print(next_page)
next_page.click()
getLinks(http://www.zillow.com/homes/for_rent/Jackson-County-MO/house,mobile_type/1804_rid/6m_days/39.198737,-93.6866,38.873394,-95.026932_rect/9_zm/)

Answer 1

要完成上述任务，您不需要beautifulsoup，可以使用webdriver 完成。试试下面的代码。

//Code to Fetch All the Link Details Through WebDriver

addr_link = driver.find_elements_by_xpath("//a[contains(@href,'homedetails')]")
for link in addr_link : 
print link.get_attribute("href")


//Code To Click On Next Button
next_btn = driver.find_elements_by_xpath("//a[text()='Next']")
next_btn.click()