BeautifulSoup 从 html 页面上的列表元素中过滤数据

Question

我正在尝试从多个 html 页面收集数据，特别是列表元素中的数据。我试图将此数据添加到字典中以供以后使用，我必须按预期提取数据，但我将数据输入到字典中没有按预期工作。我目前正在覆盖每个条目，而不是添加新条目。谁能指出我哪里出错了？

当前代码

from BeautifulSoup import BeautifulSoup
import requests
import re

person_dict = {}

.....
<snip>
<snip>
.....

soup = BeautifulSoup(response.text)

    div = soup.find('div', {'id': 'object-a'})
    ul = div.find('ul', {'id': 'object-a-1'})
    li_a = ul.findAll('a', {'class': 'title'})
    li_p = ul.findAll('p', {'class': 'url word'})
    li_po = ul.findAll('p')

    for a in li_a:
        nametemp = a.text
        name = (nametemp.split(' - ')[0])
        person_dict.update({'Name': name})     #I attempted updating
    for lip in li_p:
        person_dict['url'] = lip.text          #I attempted adding directly

    for email in li_po:   
        reg_emails = re.compile('[a-zA-Z0-9.]*' + '@')        
        person_dict['email'] = reg_emails.findall(email.text)

print person_dict # results in 1 entry being returned

测试数据

<div id="object-a">
    <ul id="object-a-1">
            <li>
              <a href="www.url.com/person" class="title">Person1</a>
              <p class="url word">www.url.com/Person1</p>
              <p>Person 1, some foobar possibly an email@address.com &nbsp;...</p>
            </li>


            <li>
              <a href="www.url.com/person" class="title">Person2</a>
              <p class="url word">www.url.com/Person1</p>
              <p>Person 2, some foobar possibly an email@address.com &nbsp;...</p>
            </li>


            <li>
              <a href="www.url.com/person" class="title">Person3</a>
              <p class="url word">www.url.com/Person1</p>
              <p>Person 3, some foobar, possibly an email@address.com &nbsp;...</p>
            </li>
    </ul>

Answer 1

是否需要使用字典取决于您，但如果您选择使用字典，最好为每个列表项使用单独的字典，而不是为所有条目使用单独的字典。

我建议您将所有条目存储在一个列表中。以下代码显示了两个建议，要么使用tuple 来存储每个项目的各种信息位，要么使用字典。

如果您只是打算显示信息或将其写入文件，tuple 解决方案会更快。

# Two possible ways of storing your data: a list of tuples, or a list of dictionaries
entries_tuples = []             
entries_dictionary = []

soup = BeautifulSoup(text)

div = soup.find('div', {'id': 'object-a'})
ul = div.find('ul', {'id': 'object-a-1'})

for li in ul.findAll('li'):
    title = li.find('a', {'class': 'title'})
    url_href = title.get('href')
    person = title.text
    url_word = li.find('p', {'class': 'url word'}).text
    emails = re.findall(r'\s+(\S+@\S+)(?:\s+|\Z)', li.findAll('p')[1].text, re.M)       # allow for multiple emails

    entries_tuples.append((url_href, person, url_word, emails))
    entries_dictionary.append({'url_href' : url_href, 'person' : person, 'url_word' : url_word, 'emails' : emails})

for url_href, person, url_word, emails in entries_tuples:
    print '{:25} {:10} {:25} {}'.format(url_href, person, url_word, emails)

print

for entry in entries_dictionary:
    print '{:25} {:10} {:25} {}'.format(entry['url_href'], entry['person'], entry['url_word'], entry['emails'])

对于您的示例 HTML，将显示以下内容：

www.url.com/person        Person1    www.url.com/Person1       [u'email@address.com']
www.url.com/person        Person2    www.url.com/Person1       [u'email@address.com']
www.url.com/person        Person3    www.url.com/Person1       [u'email@address.com', u'email@address.com']

www.url.com/person        Person1    www.url.com/Person1       [u'email@address.com']
www.url.com/person        Person2    www.url.com/Person1       [u'email@address.com']
www.url.com/person        Person3    www.url.com/Person1       [u'email@address.com', u'email@address.com']

注意，从文本中提取电子邮件地址本身就是一个完整的问题。上述解决方案可以轻松匹配实际上不是格式正确的电子邮件地址的条目，但在这里就足够了。

Answer 2

你可能会走错路。试试这样的：

from BeautifulSoup import BeautifulSoup
import re

text = open('soup.html') # You are opening the file differently
soup = BeautifulSoup(text)
list_items = soup.findAll('li')

people = []

for item in list_items:
    name = item.find('a', {'class': 'title'}).text
    url = item.find('p', {'class': 'url word'}).text
    email_text = item.findAll('p')[1].text
    match = re.search(r'[\w\.-]+@[\w\.-]+', email_text)
    email = match.group(0)

    person = {'name': name, 'url': url, 'email': email}
    people.append(person)

print people