使用 BeautifulSoup Python 从表中获取值答案

【问题标题】：get values from table with BeautifulSoup Python使用 BeautifulSoup Python 从表中获取值
【发布时间】：2014-03-06 12:35:27
【问题描述】：

我有一个表格，我在其中提取链接和文本。虽然我只能做其中之一。知道如何同时获得两者吗？

基本上我需要提取文本：“TEXT TO EXTRACT HERE”

 for tr in rows:
                    cols = tr.findAll('td')
                    count = len(cols)
                    if len(cols) >1:

                        third_column = tr.findAll('td')[2].contents
                        third_column_text = str(third_column)
                        third_columnSoup = BeautifulSoup(third_column_text)

#issue starts here. How can I get either the text of the elm <td>text here</td> or the href text<a href="somewhere.html">text here</a>
                        for elm in third_columnSoup.findAll("a"):
                            #print elm.text, third_columnSoup
                            item = { "code": random.upper(),
                                        "name": elm.text }
                            items.insert(item )

HTML 代码如下

<table cellpadding="2" cellspacing="0" id="ListResults">
    <tbody>
        <tr class="even">
            <td colspan="4">sort results: <a href=
            "/~/search/af.aspx?some=LOL&amp;Category=All&amp;Page=0&amp;string=&amp;s=a"
            rel="nofollow" title=
            "sort results in alphabetical order">alphabetical</a>&nbsp;&nbsp;|&nbsp;&nbsp;<strong>rank</strong>&nbsp;&nbsp;<a href="/as.asp#Rank">?</a></td>
        </tr>

        <tr class="even">
            <th>aaa</th>

            <th>vvv.</th>

            <th>gdfgd</th>

            <td></td>
        </tr>

        <tr class="odd">
            <td align="right" width="32">******</td>

            <td nowrap width="60"><a href="/aaa.html" title=
            "More info and direct link for this meaning...">AAA</a></td>

            <td>TEXT TO EXTRACT HERE</td>

            <td width="24"></td>
        </tr>

        <tr class="even">
            <td align="right" width="32">******</td>

            <td nowrap width="60"><a href="/someLink.html"
            title="More info and direct link for this meaning...">AAA</a></td>

            <td><a href=
            "http://www.fdssfdfdsa.com/aaa">TEXT TO EXTRACT HERE</a></td>

            <td width="24">
                <a href=
                "/~/search/google.aspx?q=lhfjl&amp;f=a&amp;cx=partner-pub-2259206618774155:1712475319&amp;cof=FORID:10&amp;ie=UTF-8"><img border="0"
                height="21" src="/~/st/i/find2.gif" width="21"></a>
            </td>
        </tr>

        <tr>
            <td width="24"></td>
        </tr>

        <tr>
            <td align="center" colspan="4" style="padding-top:6pt">
            <b>Note:</b> We have 5575 other definitions for <strong><a href=
            "http://www.ddfsadfsa.com/aaa.html">aaa</a></strong> in our
            database</td>
        </tr>
   </tbody>
</table>

【问题讨论】：

能否发布您正在解析的整个 html（或相关部分）？
嘿@alecxe 我已经更新了代码。许多 Tks。
这可能会对您有所帮助！ stackoverflow.com/questions/1817184/…

标签： python-2.7 beautifulsoup

【解决方案1】：

您可以只在td 元素上使用text 属性：

from bs4 import BeautifulSoup

html = """HERE GOES THE HTML"""

soup = BeautifulSoup(html, 'html.parser')
for tr in soup.find_all('tr'):
    columns = tr.find_all('td')
    if len(columns) > 2:
        print columns[2].text

打印：

TEXT TO EXTRACT HERE
TEXT TO EXTRACT HERE

希望对您有所帮助。

【讨论】：

打印时出现错误 third_column.text AttributeError: 'list' object has no attribute 'text'
实际上，如果我执行以下操作，它可以工作 third_column_text = str(third_column)third_columnSoup = BeautifulSoup(third_column_text) if third_columnSoup: printthird_columnSoup.text

【解决方案2】：

方法如下：

third_column = tr.find_all('td')[2].contents

                third_column_text = str(third_column)
                third_columnSoup = BeautifulSoup(third_column_text)
                if third_columnSoup:
                    print third_columnSoup.text

【讨论】：