Python：增加一个字符串

Question

我对 Python 还不是很熟悉。 我有一个像"11223300" 这样的字符串。现在我想增加该字符串的最后一个字节（从"00" 到"FF"）。我尝试将字符串转换为整数（integer=int(string,16)）并增加它，然后再将其转换回来，但这对我不起作用。也许你们中的某个人有更好的主意。

string = "11223300"
counter = int(string, 16)

for i in range(255): 
    counter = counter + 1
    IV = hex(counter)

现在我想将 IV 从十六进制转换为字符串

谢谢！

Answer 1

您可以使用format 将int 转换为您的十六进制字符串，这样就不会保留0x 前缀：

string = "11223300"
counter = int(string, 16)

for i in range(255): 
    counter = counter + 1
    IV = format(counter, 'X')
print(IV)

输出：

112233FF

Answer 2

下面的函数接受一个字符串，并从给定的字符集将其增加 n

例如，在字符集中 ['a','b','c'] ：

• "aaa" + 1 = "aab"

• "aac" + 1 = "aba"

• "acc" + 2 = "bab"

  def str_increaser(mystr, charset, n_increase):
  
      # Replaces a char in given string & index
      def replace_chr_in_str(mystr, index, char):
          mystr = list(mystr)
          mystr[index] = char
          return ''.join(mystr)
  
      # Increases the char last (n) and possibly its left neighboor (n-1).
      def local_increase(mystr, charset):
          l_cs = len(charset)
          # increasing 1 to last char if it's not the last char in charset (e.g. 'z' in lowercase ascii).
          if (charset.index(mystr[-1]) < l_cs - 1):
              mystr = replace_chr_in_str(mystr, -1, charset[charset.index(mystr[-1]) + 1])
          # else, reset last char to the first one in charset and increase the its left char, using a reducted string for recursion
          else:
              mystr = replace_chr_in_str(mystr, -1, charset[0])
              mystr = local_increase(mystr[:-1], charset) + mystr[-1]
          return mystr
  
      # Case if input = "zz...zz" in an ascii lowercase charset for instance
      if (mystr == charset[-1] * len(mystr)):
          print("str_increaser(): Input already max in charset")
      else:
          for i in range(n_increase):
              mystr = local_increase(mystr, charset)
  
      return mystr
  

这是一个例子：

# In bash : $ man ascii
# charset = map(chr, range(97, 123)) + map(chr, range(65, 91))
import string
charset = string.lowercase + string.uppercase
print(str_increaser("RfZ", charset, 2)) # outputs "Rgb"

此函数可用于获取某些字符集中的所有排列。

Answer 3

那么你真的想将字符串的最后两位更改为“FF”吗？如果是这样，很容易

string = "11223300"
modified_string = string[:-2] + "FF"

从 cmets 编辑

hex_str = "0x11223300"
for i in range(256):
    hex_int = int(hex_str, 16)
    new_int = hex_int + 0x01
    print(hex(hex_int))
    hex_str = str(hex(new_int))