Python：删除所有以大写字母开头且标点符号后不出现的单词

Question

我想使用正则表达式从文本中删除所有以大写字母开头并满足以下两个条件的单词：

1) 它们后面只能跟小写字母或“'s”（所有格）或标点符号（.,?!）。

2) 它们不在“.”、“！”之后。和“？”

我试过了

import re

myString='The name of her company is Water Company WC 123 WaTerCompany! She was going to meet Daniel. Why? Because Daniel is her boy friend. Patricia? The daughter of Susana! Look, Daniel\'s car is white'
regex='([A-Z][a-z\']*)(\s[A-Z][a-z\']*)*'
txt = re.sub(regex, " ", myString)        

我得到了

name of her company is    123    !   was going to meet  .  ?   is her boy friend.  ?   daughter of  !  ,   car is white

我想要

name of her company is  WC 123 WaTerCompany! She was going to meet . Why? Because is her boy friend. Patricia? The daughter of ! Look, car is white

Answer 1

要删除整个单词，您需要使用\b 边界锚点，这样您就不会匹配部分单词。要删除标点符号前面的单词，您可以使用否定的lookbehind，假设标点符号和第一个字母之间总是有固定数量的空格。

我将假设标点符号和下一个字母之间总是有一个空格。您始终可以通过用一个空格替换多个空格来首先规范化您的输入。

这使得正则表达式删除了这些词：

\b(?<![!?.]\s)[A-Z][a-z]*(?:'s)?\b

还有一个演示：

>>> import re
>>> myString='The name of her company is Water Company WC 123 WaTerCompany! She was going to meet Daniel. Why? Because Daniel is her boy friend. Patricia? The daughter of Susana! Look, Daniel\'s car is white'
>>> regex = r'\b(?<![!?.]\s)[A-Z][a-z]*(?:'s)?\b'
>>> re.sub(regex, " ", myString)
'  name of her company is     WC 123 WaTerCompany! She was going to meet  . Why? Because   is her boy friend. Patricia? The daughter of  ! Look,   car is white'

或在线尝试该模式，regex101。