【发布时间】:2017-02-05 20:54:10
【问题描述】:
有没有人知道任何替代方案: root = tk()
当我运行我的程序时,多个窗口同时运行,只是想知道是否有替代方法使它们不会同时打开。程序运行后立即打开的第二个窗口应在按下初始窗口上的按钮时启动。我也尝试过使用: 根 = 顶层() 但结果是一样的。 有任何想法吗?谢谢
def Search_Inventory():
#---First Window----
root = Toplevel()
root.title("Warehouse Inventory Control System")
root.configure(bg = "black")
#----Title displayed under the company logo on the first window----
Title_Screen = Label(root,
text="Warehouse Inventory Control System",
fg="grey",
bg="black",
font="Helevetica 25 bold",
pady = "50",
padx = "50",
).grid(row=3, column=4)
#----Interactive Input Boxes for the User----
#----Label to Notify what is needed in the entry box----
PN_Info_Label = Label(root,
text = "Part Number:",
fg="white",
bg="black",
font="Helevetica 15 bold",
padx = 50,
).grid(row=14, column=3, rowspan = 2)
#----Input Box for Part Number
PN_Display = StringVar()
Input_PartNumber = Entry(root,
textvariable=PN_Display,
fg = "blue",
font = "Helevtica 25 bold",
).grid(row=14, column=4)
#----A button that will proceed to the next part of the program----
Search_Button = Button(root,
text = "Search Inventory",
fg = "Blue",
bg = "Grey",
bd = 2,
font="Helevetica 15 bold",
command=lambda:Search_Prod(PN_Display.get()),
height = 1,
width = 15,
).grid(row=16, column=4,pady = 25,padx = 25,)
#----Information regarding how to enter the part number---
Info = Label(root,
text="Please Use Capitals to Enter Part Number",
fg= "red",
bg = "black",
font = "helevetica 12 bold",
).grid(row = 15, column = 4)
#----Adding the company logo to the first window----
photo = PhotoImage(file="image.gif")
photoLabel = Label(image=photo)
photoLabel.image = photo
photoLabel.grid(row=1, column=4, pady = 10)
#----Linking the Help Document----
Help_Button = Button(root,
text = "Help",
command=Help_PDF,
fg = "Red",
bg = "Black",
height = "1",
bd = "2",
font = "Helevetica 20 bold",
width = "4",
).grid(row=0, column=5, pady= 10,padx = 50, sticky = E)
#----Saying who the program was made by----
Credits = Label(root,
text = "Created By: Me",
fg = "White",
bg = "Black",
font = "Helevetica 10 underline",
).grid(row = 19, column = 5)
#To Make Sure that the window doesn't close
root.mainloop()
这就是本来打算稍后运行但立即运行的子程序。
root_menu = frame()
root_menu.title("Warehouse Inventory Control System")
root_menu.configure(bg = "black")
photo = PhotoImage(file="logo.gif")
photoLabel = Label(image=photo)
photoLabel.image = photo
photoLabel.grid(row=1, column=3,columnspan = 4, sticky = N)
Title_Screen = Label(root_menu,
text="Welcome to the SsangYong\n Warehouse Inventory Control System",
fg="grey",
bg="black",
font="Helevetica 25 bold",
pady = "50",
padx = "50",
).grid(row=2, column=3)
Search_Inventory = Button(root_menu,
command = Search_Inventory(),
text = "Search Inventory",
fg = "Blue",
bg = "Grey",
bd = 2,
font="Helevetica 12 bold",
height = 1,
width = 50,
).grid(row=16, column=3,pady = 25,padx = 25,)
Add_Stock = Button(root_menu,
text = "Add New Items",
fg = "Blue",
bg = "Grey",
bd = 2,
font="Helevetica 12 bold",
height = 1,
width = 60,
).grid(row=15, column=3,pady = 25,padx = 25,)
Print_Report = Button(root_menu,
text = "Print Stock Report",
fg = "Blue",
bg = "Grey",
bd = 2,
font="Helevetica 12 bold",
height = 1,
width = 70,
).grid(row=17, column=3,pady = 25,padx = 25,)
Help_Button = Button(root_menu,
text = "Help",
command=Help_PDF,
fg = "Red",
bg = "Black",
height = "1",
bd = "2",
font = "Helevetica 20 bold",
width = "4",
).grid(row=1, column=3,rowspan = 2, sticky= NE)
Credits = Label(root,
text = "Created By:mk",
fg = "White",
bg = "Black",
font = "Helevetica 10 underline",
).grid(row = 19, column = 5)
root_menu.mainloop()
这是最初要弹出的内容,但与另一个完全混淆。
【问题讨论】:
-
为什么在第二个文件的最后一个
Label中使用root而不是root_menu? -
顺便说一句:
var = Widget().grid()它将None分配给变量,因为grid()返回None- 如果您需要var,那么您必须分两步进行var = Widget()和var.grid()
标签: python python-3.x tkinter project root