Python/Selenium - 无法单击 www.instagram.com 上的“接受 cookie”按钮

Question

我正在尝试使用 python selenium 登录 instagram。但我必须接受 cookie 才能继续。

这是我的代码

class InstaBot:
    def __init__(self, username, pw):
        self.driver = webdriver.Chrome()
        self.driver.get('https://www.instagram.com/')
        sleep(2)
 #this is the code that im trying to use, so to click the accept button 
self.driver.find_element_by_xpath("/html/body/div[2]/div/div/div/div[2]/button[1]").click() 
        self.driver.find_element_by_xpath("//input[@name=\"username\"]")\
            .send_keys(username)
        self.driver.find_element_by_xpath("//input[@name=\"password\"]")\
            .send_keys(pw)
        self.driver.find_element_by_xpath("//a[contains(text(), 'Log in')]")\
            .click()
        sleep(4)

问题是当它点击接受按钮时它什么也不做。有什么想法吗？

Answer 1

应该点击接受登录及其后面的两个元素。等到元素变为可点击，然后点击它。

WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Accept']"))).click()
#Your code
WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "#loginForm > div > div:nth-child(3) > button"))).click()  
WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Save Info']"))).click()
WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Turn On']"))).click()

导入

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait 
from selenium.webdriver.support import expected_conditions as EC

Answer 2

试试这个：

self.driver.find_element_by_xpath("//button[text()='Accept']").click()

我在这里发布了我的解决方案：Accepting cookies error with Python/Selenium on www.instagram.com

Answer 3

您可以使用此代码：

from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver import Chrome
from selenium import webdriver

alert=WebDriverWait(driver, 15).until(EC.element_to_be_clickable((By.XPATH, '//button[contains(text(), "Accept All")]'))).click()