【发布时间】:2016-12-05 20:14:53
【问题描述】:
我正在尝试从此webpage 中提取数据,但由于页面的 HTML 格式不一致,我遇到了一些问题。我有一个 OGAP ID 列表,我想为我遍历的每个 OGAP ID 提取基因名称和任何文献信息 (PMID #)。感谢此处的其他问题和 BeautifulSoup 文档,我能够始终如一地获得每个 ID 的基因名称,但我在文献部分遇到了麻烦。下面是几个突出显示不一致之处的搜索词。
有效的 HTML 示例
搜索词:OG00131
<tr>
<td colspan="4" bgcolor="#FBFFCC" class="STYLE28">Literature describing O-GlcNAcylation:
<br> PMID:
<a href="http://www.ncbi.nlm.nih.gov/pubmed/20068230">20068230</a>
[CAD, ETD MS/MS]; <br>
<br>
</td>
</tr>
不起作用的 HTML 示例
搜索词:OG00020
<td align="top" bgcolor="#FBFFCC">
<div class="STYLE28">Literature describing O-GlcNAcylation: </div>
<div class="STYLE28">
<div class="STYLE28">PMID:
<a href="http://www.ncbi.nlm.nih.gov/pubmed/16408927?dopt=Citation">16408927</a>
[Azide-tag, nano-HPLC/tandem MS]
</div>
<br>
Site has not yet been determined. Use
<a href="parser2.cgi?ACLY_HUMAN" target="_blank">OGlcNAcScan</a>
to predict the O-GlcNAc site. </div>
</td>
这是我目前的代码
import urllib2
from bs4 import BeautifulSoup
#define list of genes
#initialize variables
gene_list = []
literature = []
# Test list
gene_listID = ["OG00894", "OG00980", "OG00769", "OG00834","OG00852", "OG00131","OG00020"]
for i in range(len(gene_listID)):
print gene_listID[i]
# Specifies URL, uses the "%" to sub in different ogapIDs based on a list provided
dbOGAP = "https://wangj27.u.hpc.mssm.edu/cgi-bin/DB_tb.cgi?textfield=%s&select=Any" % gene_listID[i]
# Opens the URL as a page
page = urllib2.urlopen(dbOGAP)
# Reads the page and parses it through "lxml" format
soup = BeautifulSoup(page, "lxml")
gene_name = soup.find("td", text="Gene Name").find_next_sibling("td").text
print gene_name[1:]
gene_list.append(gene_name[1:])
# PubMed IDs are located near the <td> tag with the term "Data and Source"
pmid = soup.find("span", text="Data and Source")
# Based on inspection of the website, need to move up to the parent <td> tag
pmid_p = pmid.parent
# Then we move to the next <td> tag, denoted as sibling (since they share parent <tr> (Table row) tag)
pmid_s = pmid_p.next_sibling
#for child in pmid_s.descendants:
# print child
# Now we search down the tree to find the next table data (<td>) tag
pmid_c = pmid_s.find("td")
temp_lit = []
# Next we print the text of the data
#print pmid_c.text
if "No literature is available" in pmid_c.text:
temp_lit.append("No literature is available")
print "Not available"
else:
# and then print out a list of urls for each pubmed ID we have
print "The following is available"
for link in pmid_c.find_all('a'):
# the <a> tag includes more than just the link address.
# for each <a> tag found, print the address (href attribute) and extra bits
# link.string provides the string that appears to be hyperlinked.
# In this case, it is the pubmedID
print link.string
temp_lit.append("PMID: " + link.string + " URL: " + link.get('href'))
literature.append(temp_lit)
print "\n"
因此,似乎元素就是将代码抛出循环的原因。有没有办法搜索带有文本“PMID”的任何元素并返回其后的文本(如果有 PMID 编号,则返回 url)?如果没有,我是否只想检查每个孩子,寻找我感兴趣的文本?
我使用的是 Python 2.7.10
【问题讨论】:
标签: python html beautifulsoup