【发布时间】:2016-12-26 16:02:02
【问题描述】:
我有一个带有抽象受保护方法的抽象基类
abstract class AbstractSample
{
abstract protected function getConnection();
}
以及将受保护方法重新定义为公共的子类:
class ConcreteSample extends AbstractSample
{
public function getConnection()
{
return 'connection resource';
}
}
这是我要测试的类:
class Caller
{
protected $_sample;
public function __construct(ConcreteSample $sample)
{
$this->_sample = $sample;
}
public function method()
{
$conn = $this->_sample->getConnection();
return $conn;
}
}
以及测试单元本身:
class Sample_Test extends \PHPUnit_Framework_TestCase
{
public function test_getConnection()
{
$RESOURCE = 'mocked resource';
$mSample = \Mockery::mock(ConcreteSample::class);
$mSample
->shouldReceive('getConnection')->once()
->andReturn($RESOURCE);
$obj = new Caller($mSample);
$res = $obj->method();
$this->assertEquals($RESOURCE, $res);
}
}
当我运行测试时出现错误:
InvalidArgumentException : getConnection() cannot be mocked as it a protected method and mocking protected methods is not allowed for this mock
/.../vendor/mockery/mockery/library/Mockery.php:670
/.../vendor/mockery/mockery/library/Mockery.php:678
/.../vendor/mockery/mockery/library/Mockery.php:629
/.../var/tmp/Sample_Test.php:13
如何模拟在基类中重新定义受保护方法的公共方法?嘲讽版本是0.9.4
【问题讨论】:
-
在 github 上的 padraic/mockery 中有一个issue。
-
大富翁?
abstract protected function可以被public function覆盖吗?我会拒绝这个拉取请求... -
这是 Mockery 中的错误,已在开发分支中修复。最新版本是 0.9.5,受到影响。
标签: php testing mocking phpunit mockery