【问题标题】:Mockery: mock publicaly overridden protected method嘲弄:模拟公开覆盖受保护的方法
【发布时间】:2016-12-26 16:02:02
【问题描述】:

我有一个带有抽象受保护方法的抽象基类

abstract class AbstractSample
{
    abstract protected function getConnection();
}

以及将受保护方法重新定义为公共的子类:

class ConcreteSample extends AbstractSample
{
    public function getConnection()
    {
        return 'connection resource';
    }
}

这是我要测试的类:

class Caller
{
    protected $_sample;

    public function __construct(ConcreteSample $sample)
    {
        $this->_sample = $sample;
    }

    public function method()
    {
        $conn = $this->_sample->getConnection();
        return $conn;
    }
}

以及测试单元本身:

class Sample_Test extends \PHPUnit_Framework_TestCase
{
    public function test_getConnection()
    {
        $RESOURCE = 'mocked resource';
        $mSample = \Mockery::mock(ConcreteSample::class);
        $mSample
            ->shouldReceive('getConnection')->once()
            ->andReturn($RESOURCE);
        $obj = new Caller($mSample);
        $res = $obj->method();
        $this->assertEquals($RESOURCE, $res);
    }
}

当我运行测试时出现错误:

InvalidArgumentException : getConnection() cannot be mocked as it a protected method and mocking protected methods is not allowed for this mock
 /.../vendor/mockery/mockery/library/Mockery.php:670
 /.../vendor/mockery/mockery/library/Mockery.php:678
 /.../vendor/mockery/mockery/library/Mockery.php:629
 /.../var/tmp/Sample_Test.php:13

如何模拟在基类中重新定义受保护方法的公共方法?嘲讽版本是0.9.4

【问题讨论】:

  • 在 github 上的 padraic/mockery 中有一个issue
  • 大富翁? abstract protected function 可以被public function 覆盖吗?我会拒绝这个拉取请求...
  • 这是 Mockery 中的错误,已在开发分支中修复。最新版本是 0.9.5,受到影响。

标签: php testing mocking phpunit mockery


【解决方案1】:

你可以试试这个:

$mSample = \Mockery::mock(ConcreteSample::class)
          ->shouldAllowMockingProtectedMethods();

【讨论】:

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