石头剪刀布游戏重置功能

Question

我是编程新手，一直在尝试掌握函数的窍门，并开始探索 Tkinter。我按照这个关于石头、纸、剪刀的教程，我有一个重置按钮，当用户点击它时，它会清除结果和用户输入的内容作为他们的选择，除了它似乎没有清除计算机的选择，即计算机选择rock，点击reset，电脑再次选择rock，reset，等等……所以我必须点击exit，然后运行程序才能得到不同的结果。

我尝试在def Reset() 和comp_pick.set("") 中分配comp_pick = None，因为我像这样清除了user_pick。我只是想弄清楚我错过了什么。

#import library
from tkinter import *
import random

#initialize window set up 
root = Tk()
root.geometry('500x500')
root.resizable(0,0)
root.title('DataFlair-Rock,Paper,Scissors')
root.config(bg ='pink3')


#heading set up 
Label(root, text = 'Rock, Paper ,Scissors' , font='arial 20 bold', bg = 'pink2').pack()


##user choice set up 
user_take = StringVar()
Label(root, text = 'choose any one: rock, paper ,scissors' , font='arial 15 bold', bg = 'pink2').place(x = 70,y=70)
Entry(root, font = 'arial 15', textvariable = user_take , bg = 'pink2').place(x=90 , y = 130)



#computer choice using the randint function
comp_pick = random.randint(1,3)
if comp_pick == 1:
    comp_pick = 'rock'
elif comp_pick ==2:
    comp_pick = 'paper'
else:
    comp_pick = 'scissors'
    



##function to play
Result = StringVar()

def play():
    user_pick = user_take.get()
    if user_pick == comp_pick:
        Result.set('It is a tie. You both have selected ' + user_pick +'.') 
    elif user_pick == 'rock' and comp_pick == 'paper':
        Result.set('You loose! Computer selected paper.')
    elif user_pick == 'rock' and comp_pick == 'scissors':
        Result.set('You win! Computer selected scissors.')
    elif user_pick == 'paper' and comp_pick == 'scissors':
        Result.set('You loose! Computer selected scissors.')
    elif user_pick == 'paper' and comp_pick == 'rock':
        Result.set('You win! Computer selected rock.')
    elif user_pick == 'scissors' and comp_pick == 'rock':
        Result.set('You loose! Computer selected rock.')
    elif user_pick == 'scissors' and comp_pick == 'paper':
        Result.set('You win! Computer selected paper.')
    else:
        Result.set('invalid: choose any one -- rock, paper, scissors')
    
        
    
##fun to reset
def Reset():
    Result.set("") 
    user_take.set("")
    comp_pick.set("")


##fun to exit
def Exit():
    root.destroy()


###### button
Entry(root, font = 'arial 10 bold', textvariable = Result, bg ='pink2',width = 50,).place(x=25, y = 250)

Button(root, font = 'arial 13 bold', text = 'PLAY'  ,padx =5,bg ='pink4' ,command = play).place(x=150,y=190)

Button(root, font = 'arial 13 bold', text = 'RESET'  ,padx =5,bg ='pink4' ,command = Reset).place(x=70,y=310)

Button(root, font = 'arial 13 bold', text = 'EXIT'  ,padx =5,bg ='pink4' ,command = Exit).place(x=230,y=310)

root.mainloop()

Answer 1

您在程序开始时设置comp_pick exactly once。相反，请在play 的开头执行此操作，以便在用户每次玩游戏时选择一个新的随机值。毕竟，每次这样你都已经选择了一个新的user_pick。

Answer 2

其他人指出了如何解决您所询问的问题。我想指出一件可能会导致未来出现问题的小事：

comp_pick = random.randint(1,3)
if comp_pick == 1:
    comp_pick = 'rock'
elif comp_pick ==2:
    comp_pick = 'paper'
else:
    comp_pick = 'scissors'

在这里，您使用变量comp_pick 来表示两个不同的东西。首先它是一个介于 1 和 3 之间的整数值。然后将它重新分配给一个字符串值以供选择。像这样为两种不同的含义重用一个变量很容易导致错误，所以你应该避免这样做。相反，请使用两个不同的变量。

Answer 3

因此，在您的代码中，您选择计算机的位置

#computer choice using the randint function
comp_pick = random.randint(1,3)
if comp_pick == 1:
    comp_pick = 'rock'
elif comp_pick ==2:
    comp_pick = 'paper'
else:
    comp_pick = 'scissors'

它在root.mainloop() 内，您必须知道.mainloop() 做了什么，您可以从here 中读取，但简而言之，这个主循环作为一种事件侦听器等，所以每当您重新设置小部件的分数时再次加载，并且您的计算机的选择也被选中，因为它在那里被执行。因此，在 mainloop 和 play() 函数之前创建一个函数并在需要时调用它

def computer_choice():
    #computer choice using the randint function
    choices = ['rock', 'paper', 'scissors']
    comp_pick = random.choice(choices)

并且在你需要的时候调用这个函数，所以你的整个代码应该是这样的：

#import library
from tkinter import *
import random

#initialize window set up 
root = Tk()
root.geometry('500x500')
root.resizable(0,0)
root.title('DataFlair-Rock,Paper,Scissors')
root.config(bg ='pink3')


#heading set up 
Label(root, text = 'Rock, Paper ,Scissors' , font='arial 20 bold', bg = 'pink2').pack()


##user choice set up 
user_take = StringVar()
Label(root, text = 'choose any one: rock, paper ,scissors' , font='arial 15 bold', bg = 'pink2').place(x = 70,y=70)
Entry(root, font = 'arial 15', textvariable = user_take , bg = 'pink2').place(x=90 , y = 130)


##function to play
Result = StringVar()

def computer_choice():
    #computer choice using the randint function
    choices = ['rock', 'paper', 'scissors']
    global comp_pick
    comp_pick = random.choice(choices)

def play():
    computer_choice()
    user_pick = user_take.get()
    if user_pick == comp_pick:
        Result.set('It is a tie. You both have selected ' + user_pick +'.') 
    elif user_pick == 'rock' and comp_pick == 'paper':
        Result.set('You loose! Computer selected paper.')
    elif user_pick == 'rock' and comp_pick == 'scissors':
        Result.set('You win! Computer selected scissors.')
    elif user_pick == 'paper' and comp_pick == 'scissors':
        Result.set('You loose! Computer selected scissors.')
    elif user_pick == 'paper' and comp_pick == 'rock':
        Result.set('You win! Computer selected rock.')
    elif user_pick == 'scissors' and comp_pick == 'rock':
        Result.set('You loose! Computer selected rock.')
    elif user_pick == 'scissors' and comp_pick == 'paper':
        Result.set('You win! Computer selected paper.')
    else:
        Result.set('invalid: choose any one -- rock, paper, scissors')
    
        
    
##fun to reset
def Reset():
    Result.set("") 
    user_take.set("")
    comp_pick.set("")


##fun to exit
def Exit():
    root.destroy()


###### button
Entry(root, font = 'arial 10 bold', textvariable = Result, bg ='pink2',width = 50,).place(x=25, y = 250)

Button(root, font = 'arial 13 bold', text = 'PLAY'  ,padx =5,bg ='pink4' ,command = play).place(x=150,y=190)

Button(root, font = 'arial 13 bold', text = 'RESET'  ,padx =5,bg ='pink4' ,command = Reset).place(x=70,y=310)

Button(root, font = 'arial 13 bold', text = 'EXIT'  ,padx =5,bg ='pink4' ,command = Exit).place(x=230,y=310)

root.mainloop()

Jai Hind，Jai Bharat