【发布时间】:2015-10-02 11:20:01
【问题描述】:
我想在我的情节中添加一个图例。到目前为止一切都很好!它一直有效,但现在我面临一个错误。
我的绘图功能代码如下:
function [ ] = plot_mti_IV( Bus_indizes, Bus_voltages,new_results, names )
global Timeslot
m={'-','--',':','-','--',':','-.','-*','-^','-.','-*','-^'};
Timeslot_temp=[1:1:Timeslot(end)];
name_index=find(Bus_voltages==1); %Find index of depicted Variable
%Initialise legend
words=['Bus' num2str(Bus_indizes(1)) names{name_index(1)}]
words=[words ;['Bus' num2str(Bus_indizes(1)) names{name_index(1)}]]
num_Bus=length(Bus_indizes);
colors = distinguishable_colors(num_Bus); %distinguishable_colors.m: Function from Mathworks File Exchange. See license for Copyright!
for i=1:length(name_index) %for number of chosen variables
for j=1:num_Bus %plot this value for all chosen busses
if j==1
plot_data=new_results{i,1}(Timeslot_temp,Bus_indizes(j)); %collect data to be plotted in array
plot(plot_data,m{i},'Color',colors(j,:) );
hold on
xlim([Timeslot(1) (Timeslot(end)+Timeslot(end)*0.05)]); %Adjustment, so that legend does not cover graph
hold on
xlabel('Time');
ylabel('Voltage');
else
words= [words ; ['Bus' num2str(Bus_indizes(j)) names{name_index(i)} ]];
plot_data=new_results{i,1}(Timeslot_temp,Bus_indizes(j)); %collect data to be plotted in array
plot(plot_data,m{i},'Color',colors(j,:) );
hold on
end
end
end
legend(words); %Add legend to graph
end
我收到一个错误
Operands to the || and && operators must be convertible to logical scalar values.
Error in legend (line 194)
elseif narg > 0 && ~ischar(varargin{1}) && ...
当我执行legend(words).
在表达式legend(words) 之前,words 的格式为:
words =
'Bus' '1' 'VBN Voltage Angle'
'Bus' '4' 'VBN Voltage Angle'
'Bus' '2' 'VBN Voltage Angle'
'Bus' '2' 'VCN Voltage Angle'
我无法理解这个错误,很高兴得到您的帮助!
嗨,啊,好吧!不知道我需要一个 1xN 矩阵...@Ander Biguri:是的,这将是我的第一个传奇条目!在这里,我将发布一个与上面代码一样的示例:
[ output_args ] = test_plot( )
figure
Timeslot=[2:1:7]
Bus_indizes=[1,2,3,5]
Bus_voltages=[0,0,0,0,1,1,0,0,0,0,0,0]
new_results=magic(12)
names=cell(1,12);
names{1,1}={'VAN Voltage Magnitude'};
names{1,2}={'VBN Voltage Magnitude'};
names{1,3}={'VCN Voltage Magnitude'};
names{1,4}={'VAN Voltage Angle'};
names{1,5}={'VBN Voltage Angle'};
names{1,6}={'VCN Voltage Angle'};
names{1,7}={'V1 Voltage Magnitude'};
names{1,8}={'V2 Voltage Magnitude'};
names{1,9}={'V0 Voltage Magnitude'};
names{1,10}={'V1 Voltage Angle'};
names{1,11}={'V2 Voltage Angle'};
names{1,12}={'V0 Voltage Angle'};
m={'-','--',':','-','--',':','-.','-*','-^','-.','-*','-^'};
Timeslot_temp=[1:1:Timeslot(end)]; %Array containing all time instants from absolute Beginning of simulation (not necessarily the first value of the timeslot) till the end of the timeslot
name_index=find(Bus_voltages==1); %Find index of depicted Variable
%Initialise words
words=['Bus' num2str(Bus_indizes(1)) names{name_index(1)}]
words=[words ;['Bus' num2str(Bus_indizes(1)) names{name_index(1)}]]
num_Bus=length(Bus_indizes);
colors = distinguishable_colors(num_Bus); %distinguishable_colors.m: Function from Mathworks File Exchange. See license for Copyright!
for i=1:length(name_index) %for number of chosen variables
for j=1:num_Bus %plot this value for all chosen busses, color is changed for every bus
if j==1
plot_data=new_results(Timeslot_temp,Bus_indizes(j)); %collect data to be plotted in array
plot(plot_data,m{i},'Color',colors(j,:) );
hold on
xlim([Timeslot(1) (Timeslot(end)+Timeslot(end)*0.05)]); %Adjustment, so that legend does not cover graph
hold on
xlabel('Time');
ylabel('Voltage'); %Label y axis with name of the chosen variable
else
words= [words ; ['Bus' num2str(Bus_indizes(j)) names{name_index(i)} ]];
plot_data=new_results(Timeslot_temp,Bus_indizes(j)); %collect data to be plotted in array
plot(plot_data,m{i},'Color',colors(j,:) );
hold on
end
end
end
legend(words); %Add legend to graph
end
【问题讨论】:
-
legend不接受二维单元格或字符串矩阵。您需要有一个 1xN 矩阵。这里的预期行为是什么?你想让第一个图例是Bus 1 VBN Voltage Angle吗?另外,你能发布一些数据来运行它吗? -
你说它一直有效。它在这种情况下有效吗?如果是这样,您能否发布最后一个有效的代码以及您希望图例显示的内容?
-
嗨,好吧!不知道我需要一个 1xN 矩阵...@Ander Biguri:是的,这将是我的第一个传奇条目!在这里,我将发布一个与上面代码类似的示例:
-
错误本身抱怨使用
&&和||,尝试将它们设置为&和|即单个实例。 -
我没有在代码中使用你上面看到的那些逻辑运算符!我无法向我解释!
标签: matlab plot format legend figure