需要检查列表中某个位置的字符是什么

Question

我需要查看列表中特定行和列的字符。我正在创建一个游戏，需要防止玩家穿过墙壁。

这是我目前的代码。

import copy
def print_house(h,sr,sc):
  th = copy.deepcopy(h)
  th[sr][sc] = "@"
  for i in th:
    print(''.join(str(x) for x in i), end='')   
    
def build_house():
    #print("Please enter the house file: ")
    house_file = "house.txt"
    housefp = open(house_file, "r")
    global myhouse
    myhouse = []
    line = housefp.readline()
    while line:
      myhouse.append(list(line))
      line = housefp.readline()
    return myhouse

def check_north(h,sr,sc):
    if sc-1 == "*":
        return False
    else:
        return True
def check_south(h,sr,sc):
    if sr+1 == "*":
        return False
    else:
        return True
def check_east(h,sr,sc):
    if sc+1 == "*":
        return False
    else:
        return True
def check_west(h,sr,sc):
    if sc-1 == "*":
        return False
    else:
        return True



def main():
    global house, startrow, startcol
    house = build_house()
    startrow, startcol = 1,3
    num_treasures = 2
    tcount = 0
    while tcount < num_treasures:
        print_house(myhouse, startrow, startcol)
        print("You can go N,S,W,E")
        command = input("Please enter where to do using the w,a,s,d keys or q to quit:")
        if command == "w" and check_north(myhouse, startrow, startcol) == True:
            trow = startrow-1
            tcol = startcol
        elif command == "a" and check_west(myhouse, startrow, startcol) == True:
            trow = startrow
            tcol = startcol-1
        elif command == "s" and check_south(myhouse, startrow, startcol) == True:
            trow = startrow+1
            tcol = startcol
        elif command == "d" and check_east(myhouse, startrow, startcol) == True:
            trow = startrow
            tcol = startcol+1
        elif command == "q":
            return
        else:
            print("Sorry, you can't go through walls")

        
        startrow,startcol = trow,tcol



main()

它还在此处使用带有地图的文本文件。文本文件名为 house.txt

***************
***       0   ********************************
***                                   6      *
***********   **************************     *
          *   *                         *    *
    ********5***************            *  t *
    *                      *            ******
    *        t         1   *
    ************************

Answer 1

如果我没看错，您尝试使用 if sc-1 == "*": 检查 char，但您应该像 set char 一样使用 get char - 使用 th[sr][sc]。

所以你需要

if th[sr][sc-1] == "*":

---

所以你需要

def check_north(h, sr, sc):
    if h[sr][sc-1] == "*":
        return False
    else:
        return True

如果您使用!= 而不是==，那么您将拥有

def check_north(h, sr, sc):
    if h[sr][sc-1] != "*":
        return True
    else:
        return False

你可以减少到

def check_north(h,sr,sc):
    return h[sr][sc-1] != "*"

因为比较 != 给出结果 True 或 False

使用==，您必须添加not 才能将True 转换为False，并将False 转换为True

def check_north(h,sr,sc):
    return not (h[sr][sc-1] == "*")