根据列拆分值之一有效更新列

Question

所以这是我的代码根据列“位置”的拆分值条件更新许多列值。该代码工作正常，但由于它按行迭代，效率不够高。谁能帮我加快这段代码的运行速度？

for index, row in df.iterrows():
    print index
    location_split =row['location'].split(':')
    after_county=False
    after_province=False
    for l in location_split:

        if l.strip().endswith('ED'):
            df[index, 'electoral_district'] = l

        elif l.strip().startswith('County'):
            df[index, 'county'] = l
            after_county = True

        elif after_province ==True:
            if l.strip()!='Ireland':
                df[index, 'dublin_postal_district'] = l

        elif after_county==True:
            df[index, 'province'] = l.strip()
            after_province = True

Answer 1

'map' 是我需要的 :)

def fill_county(column):
    res = ''
    location_split = column.split(':')

    for l in location_split:
        if l.strip().startswith('County'):
            res= l.strip()
            break
    return res

df['county'] = map(fill_county, df['location'])