【发布时间】:2017-09-23 21:39:54
【问题描述】:
我有这个 HTML 代码:
<select id="ITAAServerList" name="ITAAServerList" style="visibility:visible">
<option ServerName="SERVER01" IPAddress="192.168.46.1" StartPageName="SERVER01_Start.html">SERVER01</option>
<option ServerName="SERVER02" IPAddress="192.168.46.2" StartPageName="SERVER02_Start.html">SERVER02</option>
<option ServerName="SERVER03" IPAddress="192.168.46.3" StartPageName="SERVER03_Start.html">SERVER02</option>
</select>
<button type="submit" name="oNext" id="oNext" onclick ="OnClickNext()" class="item cursor-pointer login-button">LOGIN</button>
...
<script type="text/javascript" src="onclicknext.js"></script>
还有这个 JS 代码:
function OnClickNext() {
var oITAAServer = document.getElementById('ITAAServerList').options[this.selectedIndex].getAttribute('StartPageName');
alert(oITAAServer);
};
我无法从下拉菜单中获取 StartPageName 属性。帮忙?
【问题讨论】:
-
刚刚更新了JS代码。
标签: javascript html drop-down-menu options