如何解决“TypeError：'coroutine' object is not callable”答案

【问题标题】：How to get around "TypeError: 'coroutine' object is not callable"如何解决“TypeError：'coroutine' object is not callable”
【发布时间】：2022-01-09 19:00:32
【问题描述】：

这是我现在拥有的代码

def help_utilities(ctx):
    embed = discord.Embed(
        color=discord.Colour.dark_blue()
    )
    embed.set_author(name="help utils")
    embed.add_field(name="Decode", value="Decodes an encrypted message (Base64)")
    embed.add_field(name="Encode", value="Encodes a message in base64")
    embed.add_field(name='Embed', value='Speak through the bot, but with fancy text"', inline=False)
    embed.add_field(name="Add/Subtract/Multiply/Divide", value="Just take two values and do whatever operation with them", inline=False)
    embed.add_field(name="Reverse", value="Reverses your text :/", inline=False)
    embed.add_field(name='Say', value='Speak through the bot!', inline=False)
    author = ctx.message.author
    author.send(embed=embed)

@client.command(pass_context=True)
async def help(ctx, arg=None):
    author = ctx.message.author

    if arg is None:
        embed = discord.Embed(
            color=discord.Colour.gold()
        )
        embed.set_author(name='Help')
        embed.add_field(name="Invite", value="Sends the invite url of the bot lmao", inline=False)
        embed.add_field(name="Disclaimer", value="for the commands below you need to call them like this: .mod \n Basically the second word :sleepy:")
        embed.add_field(name="help mod", value="To see more info on my moderation commands", inline=False)
        embed.add_field(name="help utils", value="To see more info on my utility commands", inline=False)
        embed.add_field(name="help fun", value="My more fun commands :eyes:", inline=False)
        await author.send(embed=embed)
    if (arg == "utils") or (arg == "Utils"):
        help_utilities()
   # there are more If statments like this but right now I will only focus on 1
   # So you can get the idea of whats going on
    else:
        await ctx.send("bro thats not a valid argument")

目前我遇到的问题是，当我调用返回标题中所述错误的函数 "help_utilities" 时，有什么方法可以调用该函数并执行操作在带有参数“utils”的函数“help_utilities”内？

【问题讨论】：

标签： python python-3.x discord.py

【解决方案1】：

你写的

        help_utilities()

你想改为调用

        help_utilities(ctx)

报告诊断错误消息时，粘贴到完整的堆栈跟踪中会非常有帮助。

【讨论】：

【解决方案2】：

对于没有完整错误详细信息的模糊问题，我很抱歉，我解决此问题的方法是将函数更改为异步函数，并使用用户 @J_H 所述的带有“ctx”参数的 await 调用它们

async def help_utilities(ctx):
    embed = discord.Embed(
        color=discord.Colour.dark_blue()
    )
    embed.set_author(name="help utils")
    embed.add_field(name="Decode", value="Decodes an encrypted message (Base64)")
    embed.add_field(name="Encode", value="Encodes a message in base64")
    embed.add_field(name='Embed', value='Sends an embed, written like ".Embed (One word title) (Description)"', inline=False)
    embed.add_field(name="Add/Subtract/Multiply/Divide", value="Just take two values and do whatever operation with them", inline=False)
    embed.add_field(name="Reverse", value="Reverses your text :/", inline=False)
    embed.add_field(name='Say', value='Speak through the bot!', inline=False)
    author = ctx.message.author
    await author.send(embed=embed)

和

if (arg == "utils") or (arg == "Utils"):
    await help_utilities(ctx)

【讨论】：