【发布时间】:2016-10-17 14:05:20
【问题描述】:
我想检查两个词“汽车”和“摩托车”是否在 Python 中数组的每个元素中。我知道如何用in 检查一个词,但不知道如何处理两个词。非常感谢任何帮助
【问题讨论】:
-
使用逻辑与运算符:
if cond1 and cond2: -
只需使用
and运算符
标签: python
我想检查两个词“汽车”和“摩托车”是否在 Python 中数组的每个元素中。我知道如何用in 检查一个词,但不知道如何处理两个词。非常感谢任何帮助
【问题讨论】:
if cond1 and cond2:
and 运算符
标签: python
二字解法:
for string in array:
if 'car' in string and 'motorbike' in string.split():
print("Car and motorbike are in string")
检查test_words中的所有个单词是否在string中的
n-word解决方案:
test_words = ['car', 'motorbike']
contains_all = True
for string in array:
for test_word in test_words:
if test_word not in string.split()::
contains_all = False
break
if not contains_all:
break
if contains_all:
print("All words in each string")
else:
print("Not all words in each string")
【讨论】:
all(map(lambda w: w in text, ('car', 'motorbike'))) 干净多了...
if 'car' in string and 'motorbike' in string.split(): 为什么不在这两种情况下拆分?
使用辅助布尔值。
car=False
motorbike=False
for elem in array:
if "car" in elem:
car=True
if "motorbike" in elem:
motorbike=True
if car and motorbike:
break
编辑:我刚刚阅读了“在每个元素中”。只需使用 AND。
【讨论】:
print表示是否匹配
我认为一个简单的解决方案是这样的:
all(map(lambda w: w in text, ('car', 'motorbike')))
但这可能存在问题,具体取决于您需要比较的挑剔程度:
>>> text = 'Can we buy motorbikes in carshops?'
>>> all(map(lambda w: w in text, ('car', 'motorbike')))
True
“汽车”和“摩托车”这两个词不在 text 中,这仍然是 True。您可能需要完全匹配的单词。我会这样做:
>>> words = ('car', 'motorbike')
>>> text = 'Can we buy motorbikes in carshops?'
>>> set(words).issubset(text.split())
False
>>> text = 'a car and a motorbike'
>>> set(words).issubset(text.split())
True
现在它可以工作了!
【讨论】:
set转换为issubset,该方法采用iterable:set(words).issubset(text.split())
我会使用all 函数:
wanted_values = ("car", "motorbike")
all(vehicle in text for text in wanted_values)
如果我们有一个字符串列表:
l = ['some car and motorbike',
'a motorbike by a car',
'the car was followed by a motorbike']
lines_with_vehicles = [text for text in l
if all(vehicle in text for text in wanted_values)]
使用正则表达式,您可以:
# no particular order
car_and_motorbike_pattern = re.compile(r'(car.*motorbike|motorbike.*car)')
all(car_and_motorbike_pattern.search(text) for text in list_of_expressions)
# This works too
car_or_motorbike_pattern = re.compile(r'(car|motorbike)')
get_vehicles = car_or_motorbike_pattern.findall
all(len(set(get_vehicles(text))) == 2 for text in list_of_expressions)
【讨论】:
This link 为我工作: 它提供了 3 种解决方案。两种方法使用列表推导式,第三种方法使用 map + lambda 函数。
我认为没有一种简单且 Pythonic 的方法可以做到这一点。您需要使用如下丑陋的逻辑:
image_file_name = 'man_in_car.jpg'
if 'car' in image_file_name and 'man' in image_file_name:
print('"car" and "man" were found in the image_file_name')
这适用于两个单词,但是如果您需要检查很多单词,那么最好使用上面链接中的代码
我希望能够做类似的事情:
if 'car' and 'man' in image_file_name:
print('"car" and "man" were found in the image_file_name')
或者:
if any(['car','man'] in image_file_name):
print('"car" and "man" were found in the image_file_name')
但是最后这 2 段代码在 python 中还不能工作。
【讨论】:
使用此功能可以检查句子中带有“and”或“or”运算符的两个或多个关键字。
def check_words(operator = 'and', words = ['car', 'bike'],
sentence = 'I own a car but not a bike'):
if operator == 'and':
word_present = True
for w in words:
if w in sentence:
word_present = True
else:
word_present = False
return word_present
elif operator == 'or':
for w in words:
if w in sentence:
return True
else:
return False
check_words(operator = 'and', words = ['car', 'bike'],
sentence = 'I own a car but not a bike')
【讨论】: