Python中的基本刽子手游戏

Question

我一周前开始学习 Python，我正在努力专注于非常基础的项目。我被困在“刽子手游戏”中

https://www.codementor.io/@ilyaas97/6-python-projects-for-beginners-yn3va03fs
刽子手
这可能是这 6 个小程序中最难的一个 项目。这将类似于猜测数字，除了我们是 猜测这个词。用户需要猜字母，给用户没有 超过 6 次尝试猜错字母。这将意味着你 必须有一个柜台。

到目前为止，我已经编写了这段代码：

import random

name = input("Please enter your name to play Hangman! ")

print("Welcome "+name+" !. Lets play Hangman.")

wrong_attempt = int(input("How many incorrect attempts do you want ? "))

f = open('words.csv',"r")

secret_word = f.readline()
#print(secret_word)
guesses = ''
while wrong_attempt > 0 :
    c = 0
    letter = input("\nGuess a word : ")
    for char in secret_word :
        if char == letter :
            print(char,end = '')
        else :
            print('*',end = '')
            c += 1
            if c == len(secret_word) :
                wrong_attempt -= 1
                print("Bad Luck. You have ",wrong_attempt," attempts left.")
                print("The secret word is ",secret_word)

if wrong_attempt == 0 :
    print("You LOSE.")

我现在得到的输出：

Please enter your name to play Hangman! ss Welcome ss !. Lets play Hangman. How many incorrect attempts do you want ? 2

Guess a word : c c******** Guess a word : o
*o******* Guess a word : m
**m****** Guess a word : z
*********Bad Luck. You have  1  attempts left.

Guess a word : d
*********Bad Luck. You have  0  attempts left. You LOSE. The secret word is  computer

预期输出：

Please enter your name to play Hangman! ss Welcome ss !. Lets play Hangman. How many incorrect attempts do you want ? 2

Guess a word : c c******** Guess a word : o co******* Guess a word : m com****** Guess a word : z
*********Bad Luck. You have  1  attempts left.

Guess a word : d
*********Bad Luck. You have  0  attempts left. You LOSE. The secret word is  computer

在发布问题时，我也是 * 的新手。任何建议将不胜感激。

Answer 1

我想这就是你的意思：

基本上我所做的是创建一个列表并用 astriks 填充项目，然后在 char 检查中我弹出第 n 个 astriks 并用字母替换它。

import random
import sys
name = input("Please enter your name to play Hangman! ")

print("Welcome "+name+" !. Lets play Hangman.")

wrong_attempt = int(input("How many incorrect attempts do you want ? "))

f = open('words.csv',"r")

secret_word = f.readline()
#print(secret_word)
guesses = ''
word = []
for i in secret_word.strip("\n"):
    word.append("*")
while wrong_attempt > 0 :
    word_str = ''.join([str(elem) for elem in word])

    #print(word_str)
    c = 0
    letter = input("\nGuess a word : ")
    for char in secret_word :
        if char == letter :
            word.pop(c)
            word.insert(c,char)
            c += 1
        else :
            c += 1
            if c == len(secret_word) :
                wrong_attempt -= 1
                print("Bad Luck. You have ",wrong_attempt," attempts left.")
                print("The secret word is ",secret_word)
    c=0

    word_str = ''.join([str(elem) for elem in word])
    print(word_str)
    if word_str == secret_word.strip("\n"):
        print("Yeee, you won")
        sys.exit()
if wrong_attempt == 0 :
    print("You LOSE.")

Answer 2

我能看出的唯一区别是预期代码中的这一行：

猜一个字：c c******** 猜一个字：o co********** 猜一个字：m com****** 猜一个字：z

而你的是：

猜一个字：c c******** 猜一个字：o

*o******* 猜一个词：m **m****** 猜一个字：z

所以尝试在末尾创建一个制表符 \t 而不是在这一行中的 \n：

    letter = input("\nGuess a word : ")