如何在gridspec的绘图的另一侧使轴刻度标签可见？

Question

绘制我最喜欢的示例数据框，如下所示：

      x   val1   val2   val3
0    0.0  10.0   NaN    NaN
1    0.5  10.5   NaN    NaN
2    1.0  11.0   NaN    NaN
3    1.5  11.5   NaN  11.60
4    2.0  12.0   NaN  12.08
5    2.5  12.5  12.2  12.56
6    3.0  13.0  19.8  13.04
7    3.5  13.5  13.3  13.52
8    4.0  14.0  19.8  14.00
9    4.5  14.5  14.4  14.48
10   5.0   NaN  19.8  14.96
11   5.5  15.5  15.5  15.44
12   6.0  16.0  19.8  15.92
13   6.5  16.5  16.6  16.40
14   7.0  17.0  19.8  18.00
15   7.5  17.5  17.7    NaN
16   8.0  18.0  19.8    NaN
17   8.5  18.5  18.8    NaN
18   9.0  19.0  19.8    NaN
19   9.5  19.5  19.9    NaN
20  10.0  20.0  19.8    NaN

我有两个子图，出于某些其他原因，我最好使用 gridspec。绘图代码如下（它非常全面，所以我想避免对代码进行重大更改，否则它们可以完美运行并且不会做一个不重要的细节）：

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import gridspec
import matplotlib as mpl

df = pd.read_csv('H:/DocumentsRedir/pokus/dataframe.csv', delimiter=',')

# setting limits for x and y
ylimit=(0,10)
yticks1=np.arange(0,11,1)
xlimit1=(10,20)
xticks1 = np.arange(10,21,1)

# general plot formatting (axes colour, background etc.)
plt.style.use('ggplot')
plt.rc('axes',edgecolor='black')
plt.rc('axes', facecolor = 'white')
plt.rc('grid', color = 'grey')
plt.rc('grid', alpha = 0.3) # alpha is percentage of transparency
colours = ['g','b','r']
title1 = 'The plot'

# GRIDSPEC INTRO - rows, cols, distance of individual plots
fig = plt.figure(figsize=(6,4))
gs=gridspec.GridSpec(1,2, hspace=0.15, wspace=0.08,width_ratios=[1,1])

## SUBPLOT of GRIDSPEC with lines 
# the first plot
axes1 = plt.subplot(gs[0,0])  

for count, vals in enumerate(df.columns.values[1:]):

    X = np.asarray(df[vals])

    h = vals
    p1 = plt.plot(X,df.index,color=colours[count],linestyle='-',linewidth=1.5,label=h) 

# formatting
p1 = plt.ylim(ylimit) 
p1 = plt.yticks(yticks1, yticks1, rotation=0) 
p1 = axes1.yaxis.set_minor_locator(mpl.ticker.MultipleLocator(0.1))
p1 = plt.setp(axes1.get_yticklabels(),fontsize=8)
p1 = plt.gca().invert_yaxis()
p1 = plt.ylabel('x [unit]', fontsize=14)
p1 = plt.xlabel("Value [unit]", fontsize=14)
p1 = plt.tick_params('both', length=5, width=1, which='minor', direction = 'in')
p1 = axes1.xaxis.set_minor_locator(mpl.ticker.MultipleLocator(0.1))
p1 = plt.xlim(xlimit1)
p1 = plt.xticks(xticks1, xticks1, rotation=0)
p1 = plt.setp(axes1.get_xticklabels(),fontsize=8)
p1 = plt.legend(loc='best',fontsize = 8, ncol=2)   #

# the second plot (something random)
axes2 = plt.subplot(gs[0,1]) 

for count, vals in enumerate(df.columns.values[1:]):

   nonans = df[vals].dropna()
   result=nonans-0.5

   p2 = plt.plot(result,nonans.index,color=colours[count],linestyle='-',linewidth=1.5)

p2 = plt.ylim(ylimit)
p2 = plt.yticks(yticks1, yticks1, rotation=0)
p2 = axes2.yaxis.set_minor_locator(mpl.ticker.MultipleLocator(0.1))
p2 = plt.gca().invert_yaxis()
p2 = plt.xlim(xlimit1)
p2 = plt.xticks(xticks1, xticks1, rotation=0)
p2 = axes2.xaxis.set_minor_locator(mpl.ticker.MultipleLocator(0.1))
p2 = plt.setp(axes2.get_xticklabels(),fontsize=8)
p2 = plt.xlabel("Other value [unit]", fontsize=14)
p2 = plt.tick_params('x', length=5, width=1, which='minor', direction = 'in')
p2 = plt.setp(axes2.get_yticklabels(), visible=False)

fig.suptitle(title1, size=16)
plt.show()

但是，是否可以在右侧显示第二个子图的 y 刻度标签？当前代码产生这个：

我想知道是否有一种简单的方法可以做到这一点：

Answer 1

试试类似的东西

axes2.yaxis.tick_right()

随便看看Python Matplotlib Y-Axis ticks on Right Side of Plot。

Answer 2

不，好的，发现这正是我想要的。 我希望 TICKS 在两边，只是标签在右边。上面的解决方案从子图的左侧删除了我的刻度，这看起来不太好。但是，这个answer 似乎得到了正确的解决方案:) 总结一下： 要获得两侧的刻度和右侧的标签，这就是修复它的方法：

axes2.yaxis.tick_right(‌​) 
axes2.yaxis.set_ticks_p‌​osition('both')

如果你需要同样的 x 轴，那就是axes2.xaxis.tick_top(‌​)