从 json/Dict Python 中删除密钥

Question

我正在尝试从我的 json 输出中删除一些键、值，但似乎没有任何效果。

代码解决方案基本上是将csv转换为json，然后从中删除不需要的键。

import csv, json
import pandas as pd
import os

def make_json(csvFilePath, jsonFilePath):
    data = {}
    with open(csvFilePath, encoding='utf-8') as csvf:
        csvReader = csv.DictReader(csvf)
        for rows in csvReader:
            
            key = rows['ipadd']
            data[key] = rows
            #used del but not working as expected
            #del data['number']
    with open(jsonFilePath, 'w', encoding='utf-8') as jsonf:
        jsonf.write(json.dumps(data, indent=4))


csvFilePath = r'csvfile.csv'
jsonFilePath = r'demo.json'

make_json(csvFilePath, jsonFilePath)

我试过del data['key_name']。 想在创建 json 之前操作 csv，但是 key 不能用于创建 json。

{
    "some_random_key": {
        "number": "12345",
        "ipadd": "some_random_key",
        "version": "0",
        "name": "superman",
        "devicename": "0",
        "osversion": "0"
    },
    "some_random_key2": {
        "number": "54321",
        "ipadd": "some_random_key2",
        "version": "0",
        "name": "batman",
        "devicename": "0",
        "osversion": "0"
    }
}

预期结果：

{
    "some_random_key": {
        "version": "0",
        "name": "superman",
        "devicename": "0",
        "osversion": "0"
    },
    "some_random_key2": {
        "version": "0",
        "name": "batman",
        "devicename": "0",
        "osversion": "0"
    }
}

Answer 1

您正在寻找 dict.pop()，这正是您所需要的。