如何在python中解析json数据时解析多索引值并创建csv文件

Question

我有几个静态键列 EmployeeId、type 和几个来自第一个 FOR 循环的列。

在第二个 FOR 循环中，如果我有一个特定的键，那么只有值应该附加到现有的数据框列，否则无论从第一个 for 循环获取的列应该保持不变。

第一个 For 循环输出：

"EmployeeId","type","KeyColumn","Start","End","Country","Target","CountryId","TargetId"
"Emp1","Metal","1212121212","2000-06-17","9999-12-31","","","",""

在第二个 For 循环之后，我有以下输出：

"EmployeeId","type","KeyColumn","Start","End","Country","Target","CountryId","TargetId"
"Emp1","Metal","1212121212","2000-06-17","9999-12-31","","AMAZON","1",""
"Emp1","Metal","1212121212","2000-06-17","9999-12-31","","FLIPKART","2",""

根据代码，如果我有可用的员工标签，我有超过 2 条记录，但我可能有几个没有员工标签的 json 文件，那么输出应该与第一个循环输出相同。

但是根据我的代码，我得到了 0 条记录。如果我的编码方式错误，请帮助我。

真的很抱歉 - 如果提问的方式不清楚，因为我是 python 新手。请在下面的超链接中找到代码

请在下面找到代码

    for i in range(len(json_file['enty'])):
        temp = {}
        temp['EmployeeId'] = json_file['enty'][i]['id']
        temp['type'] = json_file['enty'][i]['type']
        for key in json_file['enty'][i]['data']['attributes'].keys():        
            try:
                temp[key] = json_file['enty'][i]['data']['attributes'][key]['values'][0]['value']
            except:
                temp[key] = None      

        for key in json_file['enty'][i]['data']['attributes'].keys(): 
            if(key == 'Employee'):
                for j in range(len(json_file['enty'][i]['data']['attributes']['Employee']['group'])):
                    for key in json_file['enty'][i]['data']['attributes']['Employee']['group'][j].keys():
                        try:
                            temp[key] = json_file['enty'][i]['data']['attributes']['Employee']['group'][j][key]['values'][0]['value']
                        except:
                            temp[key] = None

                    temp_df = pd.DataFrame([temp])
                    df = pd.concat([df, temp_df], sort=True)

    # Rearranging columns
    df = df[['EmployeeId', 'type'] + [col for col in df.columns if col not in ['EmployeeId', 'type']]]

    # Writing the dataset
    df[columns_list].to_csv("Test22.csv", index=False, quotechar='"', quoting=1)

如果员工标签不可用，我将获得 0 条记录作为输出，但我希望根据第一个 FOR 循环的输出有 1 条记录。如果“员工标签”可用，那么我期待 2 条记录以及我的静态列“EmployeeId”、“type”、“KeyColumn”、“Start”、“End”，否则如果标签不可用，则所有静态列列 "EmployeeId","type","KeyColumn","Start","End"，其余列为空白

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Answer 1

修改代码的长期解决方案，因此添加一个循环、更改索引以及修改 range 参数：

df = pd.DataFrame()

num = max([len(v) for k,v in json_file['data'][0]['data1'].items()])
for i in range(num):
    temp = {}
    temp['Empid'] = json_file['data'][0]['Empid']
    temp['Empname'] = json_file['data'][0]['Empname']
    for key in json_file['data'][0]['data1'].keys():
        if key not in temp:
            temp[key] = []
        try:
            for j in range(len(json_file['data'][0]['data1'][key])):
                temp[key].append(json_file['data'][0]['data1'][key][j]['relative']['id']) 
        except:
            temp[key] = None                    
    temp_df = pd.DataFrame([temp])
    df = pd.concat([df, temp_df],ignore_index=True)
for i in json_file['data'][0]['data1'].keys():
    df[i] = pd.Series([x for y in df[i].tolist() for x in y]).drop_duplicates()

现在：

print(df)

是：

  Empid Empname    XXXX   YYYYY
0  1234     ABC  Naveen   Kumar
1  1234     ABC     NaN  Rajesh