将鼠标光标位置设置为对象标题

Question

我想通过窗口内的鼠标光标位置设置对象u1的标题。

import turtle
import pygame
import time

win = turtle.Screen()#window
win.title("eagle.py")
win.setup(1920,1080)
win.bgcolor("black")
win.bgpic("triangle")


c1 = turtle.Turtle()#cloud1
c1.speed(0)
c1.penup()
c1.setposition(-1075, 256)
c1.color("white")
c1.shape("triangle")
c_speed = 1 #cloudspeed

u1 = turtle.Turtle()#user1
mouse_pos = pygame.mouse.get_pos()
u1.shape("triangle")
u1.color("red")
u1.speed(0)
u1.setposition(0,0)
u1.setheading(mouse_pos)
u1.penup()
u_speed = 10 #playerspeed


def u1_r():
    x = u1.xcor()
    x += u_speed
    u1.setx(x)
def u1_l():
    x = u1.xcor()
    x -= u_speed
    u1.setx(x)
def u1_up():
    y = u1.ycor()
    y += u_speed
    u1.sety(y)
def u1_down():
    y = u1.ycor()
    y -= u_speed
    u1.sety(y)


while True:
    win.update()
    time.sleep(1/160)
    c1.setx(c1.xcor() + c_speed)
    if c1.xcor() > 1075:
        c1.goto(-1075, 256)
    win.listen()
    win.onkeypress(u1_r, "d")
    win.onkeypress(u1_l, "a")
    win.onkeypress(u1_up, "w")
    win.onkeypress(u1_down, "s")

程序运行后立即关闭。我做错了什么？

Answer 1

您拥有以下事实：

win.listen()
win.onkeypress(u1_r, "d")
win.onkeypress(u1_l, "a")
win.onkeypress(u1_up, "w")
win.onkeypress(u1_down, "s")

在循环中表示您对工作环境没有基本了解。让我们重新开始，折腾 pygame 和 time，只在 turtle 框架内工作：

from turtle import Screen, Turtle

def player_r():
    player.setheading(0)
    player.setx(player.xcor() + player_speed)

def player_l():
    player.setheading(180)
    player.setx(player.xcor() - player_speed)

def player_up():
    player.setheading(90)
    player.sety(player.ycor() + player_speed)

def player_down():
    player.setheading(270)
    player.sety(player.ycor() - player_speed)

def move():
    cloud.setx(cloud.xcor() + cloud_speed)

    if cloud.xcor() > 940:
        cloud.goto(-940, 256)

    screen.update()

    screen.ontimer(move)

screen = Screen()
screen.setup(1920, 1080)
screen.bgcolor('black')
screen.tracer(False)

cloud = Turtle()
cloud.shape('circle')
cloud.shapesize(1, 3)
cloud.color('white')

cloud.penup()
cloud.setposition(-940, 256)

cloud_speed = 1

player = Turtle()
player.shape('turtle')
player.color('red')

player.penup()

player_speed = 10

screen.onkeypress(player_r, 'd')
screen.onkeypress(player_l, 'a')
screen.onkeypress(player_up, 'w')
screen.onkeypress(player_down, 's')
screen.listen()

move()

screen.mainloop()

Answer 2

在您的代码中，字符串位于标题中。而是放变量。

u1 = turtle.Turtle()
mouse_pos = pygame.mouse.get_pos()
u1.heading(mouse_pos)  # variable

编辑：这对我有用，三角形移动..

一开始似乎需要pygame.init()。

u1.setheading 里面有一个数字，而不是元组。这是为了角度。 (man turtle)

import turtle
import pygame
import time

pygame.init()

win = turtle.Screen()#window
win.title("eagle.py")
win.setup(1920,1080)
win.bgcolor("black")
win.bgpic() # changed


c1 = turtle.Turtle()#cloud1
c1.speed(0)
c1.penup()
c1.setposition(-1075, 256)
c1.color("white")
c1.shape("triangle")
c_speed = 1 #cloudspeed

u1 = turtle.Turtle()#user1
mouse_pos = pygame.mouse.get_pos()
u1.shape("triangle")
u1.color("red")
u1.speed(0)
u1.setposition(0,0)
u1.setheading(0)  # to be changed, setheading(int)
u1.penup()
u_speed = 10 #playerspeed


def u1_r():
    x = u1.xcor()
    x += u_speed
    u1.setx(x)
def u1_l():
    x = u1.xcor()
    x -= u_speed
    u1.setx(x)
def u1_up():
    y = u1.ycor()
    y += u_speed
    u1.sety(y)
def u1_down():
    y = u1.ycor()
    y -= u_speed
    u1.sety(y)


while True:
    win.update()
    time.sleep(1/160)
    c1.setx(c1.xcor() + c_speed)
    if c1.xcor() > 1075:
        c1.goto(-1075, 256)
    win.listen()
    win.onkeypress(u1_r, "d")
    win.onkeypress(u1_l, "a")
    win.onkeypress(u1_up, "w")
    win.onkeypress(u1_down, "s")

Answer 3

turtle.heading() 需要一个数字参数，以度数指定航向。

我认为您不能同时使用pygame 和turtle 模块。两者都有自己的绘制图形和获取鼠标当前位置的方式，所以理论上你可以使用任何一种。

无论您使用的是哪一个，您都需要从鼠标的 x、y 位置计算航向角。

以下是测量与 x、y 位置原点的角度的方法（假设其 x 值不为零）：

import math

x, y = ... # Mouse position.
print(math.degrees(math.atan(y/x)))