Jython 编码问题答案

【问题标题】：Jython Coding IssueJython 编码问题
【发布时间】：2015-03-26 18:01:20
【问题描述】：

设计一个程序，让用户将 12 个月中每个月的总降雨量输入到一个列表中。该程序应计算并显示当年的总降雨量、月平均降雨量以及最高和最低降雨量的月份。

def main():
January = requestNumber ("Enter the amount of rainfall for the month of January:") 
February = requestNumber ("Enter the amount of rainfall for the month of February:") 
March = requestNumber ("Enter the amount of rainfall for the month of March:") 
April = requestNumber ("Enter the amount of rainfall for the month of April:") 
May = requestNumber ("Enter the amount of rainfall for the month of May:") 
June = requestNumber ("Enter the amount of rainfall for the month of June:") 
July = requestNumber ("Enter the amount of rainfall for the month of July:") 
August= requestNumber ("Enter the amount of rainfall for the month of August:") 
September = requestNumber ("Enter the amount of rainfall for the month of September:") 
October = requestNumber ("Enter the amount of rainfall for the month of October:") 
November = requestNumber ("Enter the amount of rainfall for the month of November:") 
December = requestNumber ("Enter the amount of rainfall for the month of December:") 

Year = [January, February, March, April, May, June, July, August, September, October, November, December] 

total_rainfall = (sum(Year))
showInformation("The total rainfall for the year is:" + str(total_rainfall))

monthly_average = (sum(Year)) / 12
showInformation ("The monthly average for the year is:" +  str(monthly_average))

这是我到目前为止的代码。我真的在努力解决问题的最后一部分，即显示降雨量最高和最低的月份。我知道如何使用最大和最小来显示数字，但我不知道如何获得与最大和最小降雨量相对应的月份。

感谢任何人都可以给我的任何帮助，这是在 Jython 中。

【问题讨论】：

将值存储为字典 {January : 12} 。那么你就可以轻松读取列表中的values，然后得到最低和最高

标签： python jython

【解决方案1】：

解决方案 1：

将月份名称列表添加到您的程序中：

Names = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
Year = [January, February, March, April, May, June, July, August, September, October, November, December]

然后，一旦获得用户输入，同时对两个列表进行排序：

monthsSorted = sorted( zip(Names, Year), cmp=lambda (x1, y1), (x2, y2) : y2 - y1 )

print "MAX=%s" % str(monthsSorted[0])
print "MIN=%s" % str(monthsSorted[-1:])

zip() 将从两个中创建这样的列表：

zip( [1,2,3], [a,b,c] ) -> [(1,a), (2,b), (3, c)]

然后按第二个分量（雨量）排序。

现在最大的月份在monthsSorted的前面，最小的是它的最后一个元素。

解决方案 2：遍历所有相互比较的元素，就像一轮冒泡排序：

print "MAX=%s" % str( reduce(lambda (x1, y1), (x2, y2) : (x1, y1) if y1 > y2 else (x2, y2), zip(Names, Year)) )

print "MIN=%s" % str ( reduce(lambda (x1, y1), (x2, y2) : (x1, y1) if y1 < y2 else (x2, y2), zip(Names, Year)) )

【讨论】：