【发布时间】:2013-06-09 02:30:04
【问题描述】:
好的,所以对于一个任务,我必须创建一个函数crop(),它会在test_crop() 中裁剪一张图片。这是代码。
def crop(pict, startX, startY, endX, endY):
width = endX - startX + 1
height = endY - startY + 1
canvas = makeEmptyPicture(width, height)
targetX = 100
for sourceX in range(45,200):
targetY = 100
for sourceY in range(25,200):
color = getColor(getPixel(pict, sourceX, sourceY))
setColor(getPixel(canvas, targetX, targetY), color)
targetY = targetY + 1
targetX = targetX + 1
show(pict)
show(canvas)
return canvas
def test_crop():
setMediaPath()
pict = makePicture("redMotorcycle.jpg")
croppedPict = crop(pict, 100, 100, 700, getHeight(pict)/2)
show(pict)
show(croppedPict)
这段代码出现错误:
setColor(getPixel(canvas, targetX, targetY), color)
上面写着"Inappropriate argument (of correct type. An error occured attempting to pass an argument to a function."
谁能告诉我它有什么问题?和教科书上的代码是一样的。
【问题讨论】:
-
您能复制并粘贴确切的错误消息吗?
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当然,它说:“参数值不正确(类型正确)。尝试将参数传递给函数时发生错误。”
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您使用的是什么版本的 jython?
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JES(Jython 学生环境)