我将如何使用 while 循环来获取多个输入？答案

【问题标题】：How would I use a while loop to get multiple inputs?我将如何使用 while 循环来获取多个输入？
【发布时间】：2020-05-02 08:46:52
【问题描述】：

我想编写一个程序，要求用户输入订票的客户数量，读取输入的数字，执行循环询问每个客户的年龄，并确定每个客户的单价。到目前为止，我的代码只有 if else 语句：

if (customerP <4){
    System.out.println("The unit Price of customer 1 is: 0");
}else {
    if(customerP <13) {
        System.out.println("The unit price of customer 1 is: 5");
    }else {
        if(customerP <19) {
            System.out.println("The unit price of customer 1 is: 8");
        }else {
            System.out.println("The unit price of customer 1 is: 10");
        }
    }    
}

如何添加一个 while 循环来询问每个客户的年龄？

【问题讨论】：

在一个命令中查看else if，避免像这里一样重叠

标签： java while-loop do-while

【解决方案1】：

给你：

Scanner scanner = new Scanner(System.in);

System.out.println("Enter No of Customers: ");
int noCustomers = scanner.nextInt();

if (noCustomers < 1) {
     throw new IllegalArgumentException("No of Customers has to be 1 or greater");
}

int[] customerAges = new int[noCustomers];

for (int i = 0; i < noCustomers; i++) {
    System.out.println("Enter age for customer: " + i);
    customerAges[i] = scanner.nextInt();
}

System.out.println("Ages: " + Arrays.toString(customerAges));

【讨论】：

【解决方案2】：

下面提供了使用while循环的代码

Scanner sc = new Scanner(System.in);

int customerCount = sc.nextInt();

int[] ageOfCustomers = new int[customerCount];
int i=0;
while(customerCount-- > 0) {

    ageOfCustomers[i++] = sc.nextInt();
}

System.out.println(Arrays.toString(ageOfCustomers));

【讨论】：