Sequelize：查找所有匹配包含的内容（不区分大小写）

Question

我想使用 sequelize.js 在模型中查询具有包含限制的记录。我该怎么做？

这就是我现在拥有的：

Assets
  .findAll({ limit: 10, where: ["asset_name like ?", '%' + request.body.query + '%'] })
  .then(function(assets){
    return response.json({
      msg: 'search results',
      assets: assets
    });
  })
  .catch(function(error){
    console.log(error);
  });

但我收到以下错误：

   { error: operator does not exist: character varying @> unknown
       at Connection.parseE (/home/travellr/safe-star.com/SafeStar/node_modules/pg/lib/connection.js:554:11)
       at Connection.parseMessage (/home/travellr/safe-star.com/SafeStar/node_modules/pg/lib/connection.js:381:17)
       at Socket.<anonymous> (/home/travellr/safe-star.com/SafeStar/node_modules/pg/lib/connection.js:117:22)
       at emitOne (events.js:96:13)
       at Socket.emit (events.js:188:7)
       at readableAddChunk (_stream_readable.js:176:18)
       at Socket.Readable.push (_stream_readable.js:134:10)
       at TCP.onread (net.js:548:20)
     name: 'error',
     length: 209,
     severity: 'ERROR',
     code: '42883',
     detail: undefined,
     hint: 'No operator matches the given name and argument type(s). You might need to add explicit type casts.',
     position: '246',
     internalPosition: undefined,
     internalQuery: undefined,
     where: undefined,
     schema: undefined,
     table: undefined,
     column: undefined,
     dataType: undefined,
     constraint: undefined,
     file: 'parse_oper.c',
     line: '722',
     routine: 'op_error',
     sql: 'SELECT "id", "asset_name", "asset_code", "asset_icon", "asset_background", "asset_add_view", "asset_add_script", "asset_add_id_regex", "date_created", "uniqueValue", "createdAt", "updatedAt" FROM "assets" AS "assets" WHERE "assets"."asset_name" @> \'%a%\' LIMIT 10;' },
  sql: 'SELECT "id", "asset_name", "asset_code", "asset_icon", "asset_background", "asset_add_view", "asset_add_script", "asset_add_id_regex", "date_created", "uniqueValue", "createdAt", "updatedAt" FROM "assets" AS "assets" WHERE "assets"."asset_name" @> \'%a%\' LIMIT 10;' }

如何在 sequelize 中使用包含查询？

Answer 1

Assets.findAll({
        limit: 10,
        where: {
            asset_name: {
                [Op.like]: '%' + request.body.query + '%'
            }
        }
}).then(function(assets){
    return response.json({
        msg: 'search results',
        assets: assets
    });
}).catch(function(error){
    console.log(error);
});

编辑

为了使其不区分大小写，您可以使用LOWER sql 函数，但之前您还必须将request.body.query 值小写。 Sequelize 查询将如下所示

let lookupValue = request.body.query.toLowerCase();

Assets.findAll({
    limit: 10,
    where: {
        asset_name: sequelize.where(sequelize.fn('LOWER', sequelize.col('asset_name')), 'LIKE', '%' + lookupValue + '%')
    }
}).then(function(assets){
    return response.json({
        msg: 'message',
        assets: assets
    });
}).catch(function(error){
    console.log(error);
});

它的作用是将表中的asset_name 值小写，并将request.body.query 值小写。在这种情况下，您将比较两个小写字符串。

为了更好地了解在这种情况下发生了什么，我建议您查看有关sequelize.where()、sequelize.fn() 和sequelize.col() 的sequelize 文档。当尝试执行一些不寻常的查询而不是简单的findAll 或findOne 时，这些函数非常有用。

在这种情况下，sequelize 当然是您的 Sequelize 实例。

Answer 2

如果您在 Postgres 中使用 sequlize，最好使用 [Op.iLike]: `%${request.body.query}%` ，您可以忘记 sequlize 函数。

Answer 3

// search case insensitive nodejs usnig sequelize


 const sequelize = require('sequelize');
    let search = "Ajay PRAJAPATI"; // what ever you right here
    userModel.findAll({
        where: {
            firstname: sequelize.where(sequelize.fn('LOWER', sequelize.col('firstname')), 'LIKE', '%' + search.toLowerCase() + '%')
        }
    })