Django python中数组内的SQL LIKE查询

Question

我需要在数组中使用类似查询 我在 keywords_array 中有数组：["rk.keywords LIKE '%%Donut%%'", "OR rk.keywords LIKE '%%Pizza%%'"]

我需要在 raw_query 最后在 where 条件中添加它，但它正在返回单个数组（OR rk.keywords LIKE '%%Pizza%%'） ：

Views.py

                keywords_array=[]
                for i in keyword:
                    keywords={}
                    if keyword[0]==i:
                        keywords="rk.keywords LIKE '%%"+i+"%%'"
                    else:
                        keywords="OR rk.keywords LIKE '%%"+i+"%%'"
                    keywords_array.append(keywords)
                for t in keywords_array:
                    raw_query="SELECT r.id,( 3959 * Acos(Cos(Radians(" +lat +")) * Cos(Radians(lat)) * Cos( Radians(lng) - Radians("+lng+")) + Sin (Radians("+lat+")) * Sin(Radians(lat)))) AS distance FROM backend_restaurant r LEFT JOIN backend_restaurant_keywords m2m ON m2m.restaurant_id = r.id LEFT JOIN backend_restaurantkeyword rk ON m2m.id = rk.id WHERE "+ t +""

打印（原始查询）

SELECT r.id,( 3959 * Acos(Cos(Radians(30.704649)) * Cos(Radians(lat)) * Cos( Radians(lng) - Radians(76.717873)) + Sin (Radians(30.704649)) * Sin(Radians(lat)))) AS distance FROM backend_restaurant r LEFT JOIN backend_restaurant_keywords m2m ON m2m.restaurant_id = r.id LEFT JOIN backend_restaurantkeyword rk ON m2m.id = rk.id WHERE OR rk.keywords LIKE '%%Pizza%%'

Answer 1

查看代码中的 cmets 以了解您做错了什么。

keywords_array=[]
for i in keyword:
    # keywords={} # unnecessary i think
    if keyword[0]==i:
        keywords="rk.keywords LIKE '%%"+i+"%%'"
    else:
        keywords="OR rk.keywords LIKE '%%"+i+"%%'"
    keywords_array.append(keywords)

# your variable raw_query was inside for loop and so its value was getting overwritten every loop,
# therefore it contained the last element of keywords_array only
# so define the contents of string which you always want to keep outside for loop
raw_query="SELECT r.id,( 3959 * Acos(Cos(Radians(" +lat +")) * Cos(Radians(lat)) * Cos( Radians(lng) - Radians("+lng+")) + Sin (Radians("+lat+")) * Sin(Radians(lat)))) AS distance FROM backend_restaurant r LEFT JOIN backend_restaurant_keywords m2m ON m2m.restaurant_id = r.id LEFT JOIN backend_restaurantkeyword rk ON m2m.id = rk.id WHERE "

# Now use '+=' to append new text to end of string the string instead of '=' which replaces the string
for t in keywords_array:
    raw_query += t + " "  # update the string instead of overwriting it

print(raw_query)

Answer 2

你的问题是这样的：

你有一个数组Keywords=["Donut", "Pizza", "Burger"]

你想要这个循环

SELECT * FROM items WHERE name LIKE '%Pizza%' 
                       OR name LIKE '%Donut%' 
                       OR name LIKE '%Burger%';