【发布时间】:2021-01-09 01:56:21
【问题描述】:
我一直在为我的 API 寻找解决方案,但找不到。所有示例或建议均无效。有人可以帮帮我吗?或者给我什么建议?我还在学习 JQuery,所以任何帮助都会非常受欢迎..
HTML:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>New api</title>
<link rel="stylesheet" href="./style.css">
</head>
<body>
<main>
<section>
<div id="alert"></div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jqueryui/1.12.1/jquery-ui.js"></script>
<ul id="wordblock">
</ul>
<div id="result">Result</div>
</section>
<script src="./api.js"></script>
</main>
</body>
</html>
JQuery 代码:
function screenResolutionAlert(x) {
if (x.matches) {
$("#alert").html("This API doesn't work with touchpads <br> (mobiles, tablets etc) <br> please use computer or laptop with a mouse").show();
} else {
$("#alert").hide();
}
}
var x = window.matchMedia("(max-width: 1200px)")
screenResolutionAlert(x)
x.addListener(screenResolutionAlert)
//API swap words code
$(function () {
$("#wordblock").sortable();
$("#wordblock").disableSelection();
const array = ["pierogi", "gołąbki", "pies", "sześcian"];
const word = array[Math.floor(Math.random() * array.length)];
let d_word = word.split('');
shuffle(d_word);
const lis = [];
for (let i = 0; i < d_word.length; i++) {
lis.push('<li class="ui-state-default">' + d_word[i] + '</li>')
}
$('#wordblock').html(lis.join(''));
$('#wordblock').mouseup(function () {
setTimeout(() => {
let r_word = '';
$('#wordblock>li').each(function (e) {
r_word += $(this).text();
});
if (r_word == word) {
$("#result").html(`Correct! It was exactly "${r_word}"`);
} else {
$("#result").html(`Wrong! keep trying.. <br> it's not "${r_word}"`);
}
}, 0);
});
});
function shuffle(a, b, c, d) {
c = a.length;
while (c) b = Math.random() * (--c + 1) | 0, d = a[c], a[c] = a[b], a[b] = d
}
是的,我使用的是移动 Jquery 链接,但不起作用...以及任何版本的...我尝试了互联网上写的所有内容;(
【问题讨论】:
标签: javascript jquery api mobile jquery-ui-selectable