【发布时间】:2017-06-28 21:44:48
【问题描述】:
我对 android 非常陌生,无法将数据库中的结果输入屏幕上的TextView。目前,我的应用程序在单击按钮后返回一条消息。我在屏幕上有两个TextView 元素txtViewBegin 和txtViewEind。从mySql(通过php)我得到一个像22-02-2014 24-05-2017 这样的字符串,我将其拆分为Strings (.split(" ")) 的数组。
我可以使用后台工作人员的setTextView(onPostExecute 吗?)
或者我应该在我的MainActivity 中这样做吗?在这方面仍然是菜鸟。对不起。
这是我的BackgroundWorker:
public class BackgroundWorker extends AsyncTask<String,Void,String> {
Context context;
AlertDialog alertDialog;
BackgroundWorker(Context ctx){
context = ctx;
}
@Override
protected String doInBackground(String... params) {
String type = params[0];
String login_url= "http://*************/****.php";
if(type.equals("Draai")){
try {
URL url = new URL(login_url);
HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();
httpURLConnection.setRequestMethod("POST");
httpURLConnection.setDoOutput(false);
httpURLConnection.setDoInput(true);
//OutputStream outputStream = httpURLConnection.getOutputStream();
//BufferedWriter bufferedWriter = new BufferedWriter(new OutputStreamWriter(outputStream,"UTF-8"));
//String post_data = URLEncoder.encode("user_name""UTF-8")// HIER KUN JE VARIABELEN INGEVEN DIE WORDEN GEIMPLEMENTEERD IN HET PHP DOCUMENT
//bufferedWriter.write();
//bufferedWriter.flush();
// bufferedWriter.close();
//outputStream.close();
InputStream inputStream = httpURLConnection.getInputStream();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream, "iso-8859-1"));
String result ="";
String line="";
while ((line=bufferedReader.readLine()) != null){
result += line;
}
String[] separated = result.split(" ");
bufferedReader.close();
inputStream.close();
httpURLConnection.disconnect();
return result;
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (Exception e){
e.printStackTrace();
}
}
return null;
}
@Override
protected void onPreExecute() {
alertDialog = new AlertDialog.Builder(context).create();
alertDialog.setTitle("TijdsDuur");
}
@Override
protected void onPostExecute(String result) {
alertDialog.setMessage(result);
alertDialog.show();
}
@Override
protected void onProgressUpdate(Void... values) {
super.onProgressUpdate(values);
}
}
还有我的MainActivity:
public class MainActivity extends AppCompatActivity {
TextView ViewBegin, ViewEind;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ViewBegin = (TextView) findViewById(R.id.txtViewBegin);
ViewEind = (TextView) findViewById(R.id.txtViewEind);
}
public void onDraai(View view){
String type = "Draai";
BackgroundWorker backgroundWorker = new BackgroundWorker(this);
backgroundWorker.execute(type);
}
}
【问题讨论】:
标签: php android mysql android-asynctask textview