如何计算字符串多维数组的出现次数？

Question

[['Canal St & Taylor St', 'Canal St & Monroe St (*)'], ['Larrabee St & Menomonee St', 'Sheffield Ave & Kingsbury St'], ['Orleans St & Chestnut St (NEXT Apts)', 'Ashland Ave & Blackhawk St'], ['Franklin St & Monroe St', 'Clinton St & Tilden St'], ['Broadway & Barry Ave', 'Sedgwick St & North Ave'], ['State St & Kinzie St', 'Wells St & Polk St'], ['Wabash Ave & Wacker Pl', 'Clinton St & Tilden St'], ['Daley Center Plaza', 'Canal St & Monroe St (*)'], ['Daley Center Plaza', 'Canal St & Monroe St (*)'], ['Dayton St & North Ave', 'Ogden Ave & Chicago Ave'], ['Wilton Ave & Diversey Pkwy', 'Halsted St & Wrightwood Ave'], ['Canal St & Madison St', 'LaSalle St & Illinois St'], ['Theater on the Lake', 'Lakeview Ave & Fullerton Pkwy'], ['Halsted St & Maxwell St', 'Halsted St & 18th St'], ['Ravenswood Ave & Lawrence Ave', 'Clarendon Ave & Gordon Ter']]

这是我的清单。我如何计算['Canal St & Taylor St', 'Canal St & Monroe St (*)']的出现次数

输出应该是

  ['Canal St & Taylor St', 'Canal St & Monroe St (*)']  : 1
  ['Larrabee St & Menomonee St', 'Sheffield Ave & Kingsbury St'] : 2
etc 

Answer 1

你需要做这样的事情：-

super = [['Canal St & Taylor St', 'Canal St & Monroe St (*)'], ['Larrabee St & Menomonee St', 'Sheffield Ave & Kingsbury St'], ['Orleans St & Chestnut St (NEXT Apts)', 'Ashland Ave & Blackhawk St'], ['Franklin St & Monroe St', 'Clinton St & Tilden St'], ['Broadway & Barry Ave', 'Sedgwick St & North Ave'], ['State St & Kinzie St', 'Wells St & Polk St'], ['Wabash Ave & Wacker Pl', 'Clinton St & Tilden St'], ['Daley Center Plaza', 'Canal St & Monroe St (*)'], ['Daley Center Plaza', 'Canal St & Monroe St (*)'], ['Dayton St & North Ave', 'Ogden Ave & Chicago Ave'], ['Wilton Ave & Diversey Pkwy', 'Halsted St & Wrightwood Ave'], ['Canal St & Madison St', 'LaSalle St & Illinois St'], ['Theater on the Lake', 'Lakeview Ave & Fullerton Pkwy'], ['Halsted St & Maxwell St', 'Halsted St & 18th St'], ['Ravenswood Ave & Lawrence Ave', 'Clarendon Ave & Gordon Ter']]
search = ['Canal St & Taylor St', 'Canal St & Monroe St (*)']
print(super.count(search))

Answer 2

你可以在python标准模块collections中使用Counter。但是，它不允许将密钥作为list，因此您必须将其转换为tuple。

from collections import Counter

a_list = [['Canal St & Taylor St', 'Canal St & Monroe St (*)'], ['Larrabee St & Menomonee St', 'Sheffield Ave & Kingsbury St'], ['Orleans St & Chestnut St (NEXT Apts)', 'Ashland Ave & Blackhawk St'], ['Franklin St & Monroe St', 'Clinton St & Tilden St'], ['Broadway & Barry Ave', 'Sedgwick St & North Ave'], ['State St & Kinzie St', 'Wells St & Polk St'], ['Wabash Ave & Wacker Pl', 'Clinton St & Tilden St'], ['Daley Center Plaza', 'Canal St & Monroe St (*)'], ['Daley Center Plaza', 'Canal St & Monroe St (*)'], ['Dayton St & North Ave', 'Ogden Ave & Chicago Ave'], ['Wilton Ave & Diversey Pkwy', 'Halsted St & Wrightwood Ave'], ['Canal St & Madison St', 'LaSalle St & Illinois St'], ['Theater on the Lake', 'Lakeview Ave & Fullerton Pkwy'], ['Halsted St & Maxwell St', 'Halsted St & 18th St'], ['Ravenswood Ave & Lawrence Ave', 'Clarendon Ave & Gordon Ter']]

counter = Counter([tuple(item) for item in a_list])
dict(counter)

# {('Larrabee St & Menomonee St', 'Sheffield Ave & Kingsbury St'): 1,('Broadway & Barry Ave', 'Sedgwick St & North Ave'): 1, ... }

Answer 3

你可以使用count列表功能

l = [['Canal St & Taylor St', 'Canal St & Monroe St (*)'], ['Larrabee St & Menomonee St', 'Sheffield Ave & Kingsbury St'], ['Orleans St & Chestnut St (NEXT Apts)', 'Ashland Ave & Blackhawk St'], ['Franklin St & Monroe St', 'Clinton St & Tilden St'], ['Broadway & Barry Ave', 'Sedgwick St & North Ave'], ['State St & Kinzie St', 'Wells St & Polk St'], ['Wabash Ave & Wacker Pl', 'Clinton St & Tilden St'], ['Daley Center Plaza', 'Canal St & Monroe St (*)'], ['Daley Center Plaza', 'Canal St & Monroe St (*)'], ['Dayton St & North Ave', 'Ogden Ave & Chicago Ave'], ['Wilton Ave & Diversey Pkwy', 'Halsted St & Wrightwood Ave'], ['Canal St & Madison St', 'LaSalle St & Illinois St'], ['Theater on the Lake', 'Lakeview Ave & Fullerton Pkwy'], ['Halsted St & Maxwell St', 'Halsted St & 18th St'], ['Ravenswood Ave & Lawrence Ave', 'Clarendon Ave & Gordon Ter']]
for i in l:
    c = l.count(i)
    print(i, '--->' ,c)