无法从android中的自定义列表视图中获取所选项目答案

【问题标题】：Unable to get selected item from custom listview in android无法从android中的自定义列表视图中获取所选项目
【发布时间】：2015-12-31 18:21:04
【问题描述】：

我使用基本适配器创建了一个自定义列表视图。我想从列表视图中获取所选项目。我尝试了不同的解决方案，但没有一个有效。我的 ListView 代码如下所示：

class SingleRow {
        String mFetchedJobTitle;
        String mFetchedCompanyName;
        String mFetchedExperience;
        String mFetchedLocation;


        SingleRow(String mFetchedJobTitle, String mFetchedCompanyName, String mFetchedExperience, String mFetchedLocation) {
            this.mFetchedJobTitle = mFetchedJobTitle;
            this.mFetchedCompanyName = mFetchedCompanyName;
            this.mFetchedExperience = mFetchedExperience;
            this.mFetchedLocation = mFetchedLocation;

        }
    }

    class MyAdapter extends BaseAdapter {

        ArrayList<SingleRow> list;
        Context context;

        MyAdapter(Context c) {
            context = c;

            list = new ArrayList<SingleRow>();
            String[] mFetchedJobTitle1 = searchJobTitle;
            String[] mFetchedCompanyName1 = searchCompanyName;
            String[] mFetchedExperience1 = searchExperience;
            String[] mFetchedLocation1 = searchLocation;

            for (int i = 0; i < mArrayLength; i++) {

                list.add(new SingleRow(mFetchedJobTitle1[i], mFetchedCompanyName1[i], mFetchedExperience1[i], mFetchedLocation1[i] ));

            }

        }

        @Override
        public int getCount() {
            return list.size();
        }

        @Override
        public Object getItem(int position) {
            return list.get(position);
        }

        @Override
        public long getItemId(int position) {
            return position;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {

            LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            View row = inflater.inflate(R.layout.custom_search_row, parent, false);

            TextView title = (TextView) row.findViewById(R.id.textViewJobTitle);
            TextView companyName = (TextView) row.findViewById(R.id.textViewCompanyName);
            TextView experience = (TextView) row.findViewById(R.id.textViewExperience);
            TextView location = (TextView) row.findViewById(R.id.textViewLocation);


            SingleRow temp = list.get(position);
            title.setText(temp.mFetchedJobTitle);
            companyName.setText(temp.mFetchedCompanyName);
            experience.setText(temp.mFetchedExperience);
            location.setText(temp.mFetchedLocation);


            return row;
        }
    }

ListView OnItemClickListener 代码：

     mListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
                       @Override
                       public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {



  mSelectedItem =  mListView.getItemAtPosition(i).toString();
                           String mselected = (String) adapterView.getSelectedItem();

                           Log.d("selecteditem", ""+mselected);
                           Log.d("selecteditem", ""+mSelectedItem);

                       }
                   });

                }

            }

我将 mSelectedItem 的值设为：

SearchResultsActivity$SingleRow@2399b34e

如何获得准确的字符串值。任何人都可以建议我一个想法。欢迎所有建议。

【问题讨论】：

mSelectedItem 的类型是什么

标签： android android-listview android-custom-view baseadapter selecteditem

【解决方案1】：

知道了，在您的每个列表项中，您正在获取一个 SingleRow 类实例。像这样做

 mListView.getItemAtPosition(i).mFetchedJobTitle;

【讨论】：

【解决方案2】：

试试这个

    SingleRow mSelectedItem =  mListView.getItemAtPosition(i);       
    String mFetchedJobTitle = mSelectedItem.mFetchedJobTitle;
    String mFetchedCompanyName = mSelectedItem.mFetchedCompanyName;
    String mFetchedExperience = mSelectedItem.mFetchedExperience;
    String mFetchedLocation = mSelectedItem.mFetchedLocation;

【讨论】：

【解决方案3】：

adapterView.getSelectedItem() 返回对象的引用，并在将其转换为 String 时返回包含类名和存储对象的内存位置的字符串。为了得到选中的项目你可以使用这个方法

public Object getItem(int position) {
        return list.get(position);
    }

【讨论】：