二维阵列扫描仪验证答案

【问题标题】：2D array scanner validation二维阵列扫描仪验证
【发布时间】：2015-03-05 14:34:43
【问题描述】：

任何能够引导我走向正确方向的人。我正在构建一个简单的标记程序，我从 Scanner 获取输入并将其插入到我的二维数组中。我想验证我的输入，使其不低于 0 或高于 100，但如果我的数字不正确，我不希望数组移动到下一个位置。

public static void main(String[] args) 
{
    Scanner input = new Scanner(System.in);//naming the scanner
    String [] student = {"Mark","Jen","Gaby","John","Michael","James"};
    String [] subject = {"Digital electronics","Analogue electronics","Maths","Networks","Telecommunications",
            "Computer applications","Software developemnt","Workshop"};
    String [] printSub = {"Digit","Analo","Maths","Netwo","Telec","Appli","Softw","Works"};
    int maxRow = 6;//setting max row amount int
    int maxCol = 8;//set max column amount int
    int [][] mark = new int [maxRow][maxCol];//declaring the int array and setting the row & column max.
    int i = 0, j = 0;//declaring i and j for use in the for loops 
    int maxMark = 0;//declaring for use in if statement to find highest mark
    int minMark =100;//Declaring for use in if statement to find lowest mark

    for(i = 0; i < maxRow; i++)
    {
        for(j = 0; j < maxCol; j++)
        {
            System.out.print("Please enter "+student[i]+" mark for "+subject[j]+" and press return :");
            mark[i][j]= input.nextInt();
        }
    }

    for(i=0; i < maxRow; i++)
    {           
        for(j=0; j < maxCol; j++)
        {
            if (i == 0 && j == 0)
            {
                System.out.print("Student  \t");
                for(int sub = 0; sub < 8; sub++)
                {
                    System.out.print(printSub [sub]+"\t");
                }
                System.out.println();
                System.out.println();
            }
            if(i < maxRow && j == 0)
            {
                System.out.print(student[i]+"\t \t  ");
            }

            System.out.print(mark [i][j]+"\t");
        }
        System.out.println();
        System.out.println();
    }
}

我不是在寻找答案，而是在寻找更多的推动力，让我自己能够找出答案。

提前感谢您的帮助。

马特

【问题讨论】：

标签： java arrays multidimensional-array java.util.scanner

【解决方案1】：

微调：您不直接将数字插入到数组中，而是将其插入到某个临时变量中，检查它然后决定是保存还是再次询问（需要循环时）

剧透1：这是完整的解决方案，如果您想自己做，请不要看：）：

    for (i = 0; i < maxRow; i++) {
        for (j = 0; j < maxCol; j++) {
            System.out.print("Please enter ");
            int number = input.nextInt();
            boolean isItOk = false;
            while (isItOk == false) {
                if (number < 0 || number > 100) {
                    System.out.println("You shall not insert a value below 0 or bigger than 100! Try it again");
                    number = input.nextInt();
                } else {
                    isItOk = true;
                }
            }
            mark[i][j] = number;
        }
    }

Spoiler 2：这是一个更好的代码，但对于初学者，我会推荐 Spoiler 1 的方法，因为它总是可用的。在更复杂的问题中，Spoiler 2 解决方案并不总是可行的。

    for (i = 0; i < maxRow; i++) {
        for (j = 0; j < maxCol; j++) {
            System.out.print("Please enter ");
            int number = input.nextInt();
            while (number < 0 || number > 100) {
                System.out.println("You shall not insert a value below 0 or bigger than 100! Try it again");
                number = input.nextInt();
            }
            mark[i][j] = number;
        }
    }

【讨论】：

【解决方案2】：

    Scanner s = new Scanner(System.in);
    int number =0;
    System.out.print("Please enter ");
    while(true)
    {
        number = s.nextInt();
        if(number > -1 && number < 101)
            break;
        System.out.println("Marks should be between  0 and 100, Please enter");

    }

还需要验证输入是否为整数，可以通过异常处理来完成

【讨论】：