Java 2D 数组排序

Question

我正在为大学做作业，我正在努力弄清楚为什么这条线行不通

return Full_Name.compareTo(Age, Student_ID, Comm_Marks, Work_Exp_Marks,Mathematics_Marks);

我试过弄乱它，在谷歌上快速搜索错误修复，但什么也没找到（嗯……至少对我来说）

我需要做的是按字母顺序组织数组，然后是其他数组值以跟随它最初旁边的值。因此，例如，当 Full_Name 数组按字母顺序排序并且 Bruce Wayne 排序时，“RP0023”的 Student_ID 必须跟随 Bruce Wayne 以及 Age 数组和科目标记......如果这有意义的话，之后还有更多步骤，但这是需要完成的任务中最难的部分。我已经为这个问题苦苦挣扎了一个星期了。讲师建议使用比较功能进行排序，这就是我一直在尝试做的事情。

我真的很想尽快完成这个排序，这样我就可以继续分配作业，因为不进行排序就无法继续。希望我涵盖了我需要做的一切并且有意义。此外，我正在编写代码并确保它在控制台中以可读方式打印之前可以正常工作。

package javaapplicationtest;

import java.util.Arrays;
import java.util.Comparator;

public class JavaApplicationTest 
{
public static void main(String[] args) 
{
Integer[] proxyLookup = new Integer[]{0, 1, 2, 3, 4, 5, 6, 7};

    String[][] Full_Name 
            = {
                {"Bruce Wayne", "Dinah Lance", "Celina Kyle", "Clark Kent"},
                {"Barry Allen", "Barbara Gordon", "Hal Jordon", "Ray Palmer"}
            };

    int[][] Age = {
     {18, 19, 23, 34},
      {19, 16, 24, 37}
    };

     String[][] Student_ID 
             = {
                 { "RP0023", "RP0024", "RP0025", "RP0026"},
                 {"RP0027", "RP0028", "RP0029", "RP0030"}
             };    

      Double[][] Comm_Marks 
              = {
                {87.4, 67.8, 45.3, 14.5} ,
                {76.8, 54.2, 56.3, 98.2}
      };

      Double[][] Work_Exp_Marks 
              = {
                  {67.5, 72.6, 97.5, 76.2} ,
                  {83.0, 45.5, 37.1, 87.4}
              };

       Double[][] Mathematics_Marks 
               = {
                   {92.4, 54.3, 56.3, 67.3} , 
                   {23.4, 67.4, 84.4, 90.0}
               };    

    System.out.println("Unsorted Array:  \n ==============");
    for (int index : proxyLookup) 
    {
        System.out.println(Full_Name[index] + ";" + Age[index] + ";" + Student_ID[index]);
    }

      Arrays.sort(proxyLookup, new Comparator<Integer>() {
        @Override
        public int compare(Integer o1, Integer o2) {
            return Full_Name.compareTo(Age, Student_ID, Comm_Marks, Work_Exp_Marks,Mathematics_Marks);

        }
    });


     System.out.println("Sorted Aray: \n ==============");

    for (int index : proxyLookup) {
        System.out.println(Full_Name[index] + "; " + Age[index] + "; " + Student_ID[index]);
    }



}



  }

Answer 1

可能您的讲师建议将此类学生表示为班级实例，然后使用compareTo 进行比较？ 喜欢

public class Student {
    private String fullName;
    private int age;
    private String studentId;
    private double commMarks;
    private double workExpMarks;
    private double mathematicsMarks;

    public Student(String fullName, int age, String studentId, double commMarks, double workExpMarks, double mathematicMarks) {
        this.fullName = fullName;
        this.age = age;
        this.studentId = studentId;
        this.commMarks = commMarks;
        this.workExpMarks = workExpMarks;
        this.mathematicsMarks = mathematicMarks;
    }...getters and setters omitted...
}

class Calculations {
    public static void main(String[] args) {
        Student s1 = new Student("Bruce Wayne", 18, "RP0023", 87.4, 67.5, 92.4);
        Student s2 = new Student("Dinah Lance", 19, "RP0024", 67.8, 72.6, 54.3);
        ...etc...

        Student[] proxyLookup = new Student[]{s1, s2, s3, s4, s5, s6, s7, s8};
        Arrays.sort(proxyLookup, (o1, o2) -> {
            if (o1.getFullName().compareTo(o2.getFullName()) != 0)) {
                return o1.getFullName().compareTo(o2.getFullName());
            }
            if (o1.getStudentId().compareTo(o2.getStudentId()) != 0)){
                return o1.getStudentId().compareTo(o2.getStudentId());
            }
...etc... 
        });
    }
}