c# 将锯齿状数组复制到字符串答案

【问题标题】：c# Copying jagged arrays to stringsc# 将锯齿状数组复制到字符串
【发布时间】：2016-01-30 13:23:39
【问题描述】：

我的函数应该用 "&" ";" 分割一个字符串和 "," 并返回一个三重锯齿状数组，反之亦然。（来自类似数据：1,2,3;4,5,6&1,2,3;4,5,6）

我一直在努力让它工作，现在由于某种原因我得到一个 system.argumentnullexception

Array.Copy(playerOneEnts, allEnts[0], playerOneEnts.Length);
Array.Copy(playerTwoEnts, allEnts[1], playerTwoEnts.Length);

完整代码：

public string convertToString(string[][][] allEnts)
{
    string Player = string.Empty;
    string[][] playerOneEnts = new string[maxEnts][];
    string[][] playerTwoEnts = new string[maxEnts][];

    Array.Copy(allEnts[0], playerOneEnts, allEnts[0].Length);
    Array.Copy(allEnts[1], playerTwoEnts, allEnts[1].Length);

    for (int j = 0; j < playerOneEnts.Length; j++)
    {
        for (int i = 0; i < playerOneEnts[j].Length; i++)
        {
            Player += playerOneEnts[j][i] + ",";
        }

        Player = Player.TrimEnd(',');
        Player += ";";
    }

    Player = Player.TrimEnd(';');
    Player += "&";

    for (int j = 0; j < playerTwoEnts.Length; j++)
    {
        for (int i = 0; i < playerTwoEnts[j].Length; i++)
        {
            Player += playerTwoEnts[j][i] + ",";
        }

        Player = Player.TrimEnd(',');
        Player += ";";
    }

    Player = Player.TrimEnd(';');
    return Player;
}

public string[][][] convertToArray(string ents)
{
    string[] p = new string[2];
    string[][] playerOneEnts = new string[maxEnts][];
    string[][] playerTwoEnts = new string[maxEnts][];
    string[][][] allEnts = new string[2][][];

    p = ents.Split('&');

    try
    {
        playerOneEnts = p[0].Split(new[] { ";" }, StringSplitOptions.RemoveEmptyEntries).Select(chunk => chunk.Split(',')).ToArray();
        playerTwoEnts = p[1].Split(new[] { ";" }, StringSplitOptions.RemoveEmptyEntries).Select(chunk => chunk.Split(',')).ToArray();

        MessageBox.Show(playerOneEnts.Length.ToString());

        Array.Copy(playerOneEnts, allEnts[0], playerOneEnts.Length);
        Array.Copy(playerTwoEnts, allEnts[1], playerTwoEnts.Length);
    }
    catch
    {
        MessageBox.Show("unable to convert string", "Fatal Error");
    }

    return allEnts;
}

代码对我来说就像一场灾难，如果有人知道将其转换为字符串的更好方法，我会很高兴有任何想法。摆脱我的错误已经对我有足够的帮助了。

谢谢！

【问题讨论】：

标签： c# arrays jagged-arrays

【解决方案1】：

这是使用 Linq 的示例（需要 .Net 4.0）：

var source = "1,2,3;4,5,6&1,2,3;4,5,6";

string[][][] decoded = source.Split('&').Select(x => x.Split(';').Select(y => y.Split(',').ToArray()).ToArray()).ToArray();

string reencoded = String.Join("&", decoded.Select(x => String.Join(";", x.Select(y => String.Join(",", y)))));

另外，可以使用 IEnumarable 泛型来避免转换为数组。

警告：此代码不验证输入，例如数组长度。

编辑：为 .NET 3.5 重新编码：

var reencoded = String.Join("&", decoded.Select(x => String.Join(";", x.Select(y => String.Join(",", y)).ToArray())).ToArray());

【讨论】：

【解决方案2】：

您可以使用这样的嵌套 for 循环来做到这一点：

string p = "1,2,3;4,5,6&1,5,3;4,5,9";
List<List<List<string>>> result = new List<List<List<string>>>();
foreach (var a in p.Split('&'))
{
    List<List<string>> level2 = new List<List<string>>();
    foreach (var b in a.Split(';'))
    {
        level2.Add(new List<string>(b.Split(',')));
    }
    result.Add(level2);
}
var x = result[0][1][2]; // This will result in '6'.

编码类似：

string encoded;
List<string> dec1 = new List<string>();
foreach (var a in result)
{
    string e = "";
    List<string> z = new List<string>();
    foreach (var b in a)
    {
        z.Add(String.Join(",", b));
    }
    e = String.Join(";", z);
    dec1.Add(e);
}
encoded = String.Join("&", dec1);

【讨论】：