展开列表列表[重复]

Question

我有这个清单：

fxrate = 
[[['9.6587'], ['9.9742'], ['9.9203'], ['10.1165'], ['10.1087']],
 [['10.7391'], ['10.8951'], ['11.1355'], ['11.561'], ['11.7873']],
 [['8.61'], ['8.9648'], ['9.0155'], ['9.153'], ['9.1475']]]

我想用 Python 做一个这样的列表：

[[9.6587, 9.9742, 9.9203, 10.1165, 10.1087],
 [10.7391, 10.8951, 11.1355, 11.561, 11.7873],
 [8.61, 8.9648, 9.0155, 9.153, 9.1475]]

不用说，我对 Python 和一般编程还很陌生。然而，我最终得到的只是一个值列表，而不是三组列表

Answer 1

你想要做的是扁平化你的列表， 只需使用列表理解。 这将获取您拥有的任何列表列表并将其展平，以便， 您的列表只有一个深度。 即[["foo"], ["bar"],["List_of_lists"]] 将变为["foo", "bar", "complex_lists"]

flat_list = [item for sublist in l for item in sublist]

如指定here

您可以根据需要将其格式化为您的代码。 像这样：

fxrate = 
   [[['9.6587'], ['9.9742'], ['9.9203'], ['10.1165'], ['10.1087']],
   [['10.7391'], ['10.8951'], ['11.1355'], ['11.561'], ['11.7873']],
   [['8.61'], ['8.9648'], ['9.0155'], ['9.153'], ['9.1475']]]
flat_fxrate = [[item for sublist in fxrate[0] for item in sublist],[item for sublist in fxrate[1] for item in sublist],[item for sublist in fxrate[2] for item in sublist]]

例如。因为你希望它分成三部分，或者如果你打算升级它。或者为了使其更清晰，您可以使用循环并附加每个部分。像这样。注意：一般来说，使用循环会好很多，因为无论这个列表的大小是多少，它都会一直有效。

flat_fxrate = []
fxrate = 
   [[['9.6587'], ['9.9742'], ['9.9203'], ['10.1165'], ['10.1087']],
   [['10.7391'], ['10.8951'], ['11.1355'], ['11.561'], ['11.7873']],
   [['8.61'], ['8.9648'], ['9.0155'], ['9.153'], ['9.1475']]]
for x in fxrate:
    flat_fxrate.append([item for sublist in x for item in sublist])