将混合嵌套列表（混合元组和二维列表）转换为 1 个暗淡列表

Question

我有一个混合列表，包含带有元组（第二维）的列表，如下所示：

[[(0, 500), (755, 1800)], [2600, 2900], [4900, 9000], [(11000, 17200)]]

列表应如下所示

[[0, 500], [755, 1800], [2600, 2900], [4900, 9000], [11000, 17200]]

我用 map 和对 list() 转换函数的调用进行了尝试。

#Try 1: works for just the first element
experiment = map(list,cleanedSeg[0])
#Try 2: gives error int not interabel
experiment = [map(list,elem) for elem in cleanedSeg if isinstance(elem, (tuple, list))]
#Try 3: 
experiment = [list(x for x in xs) for xs in cleanedSeg]

print experiment

他们都没有解决我的问题

Answer 1

mixlist = [[(0, 500), (755, 1800)], [2600, 2900], [4900, 9000], [(11000, 17200)]]

# [[0, 500], [755, 1800], [2600, 2900], [4900, 9000], [11000, 17200]]
experiment = [list(n) if isinstance(n, tuple) else [n] for sub in mixlist for n in sub]

我尝试了以下列表理解的两个版本。上面的一个和另一个替代的地方

experiment = [list(n) if isinstance(n, tuple) else list(n) for sub in mixlist for n in sub]

此表达式给出以下错误：

TypeError: Argument of type 'int' is not iterable. 

这两个表达式的区别在于使用列表字面量 [] 和列表函数 ()。

list_literal = [n] # Gives a list literal [n]
ls = list(n) # Iterate over n's items and produce a list from that.

例如：

>>> n = (1,2,3)
>>> list_literal = [n]
>>> list_literal
[(1, 2, 3)]
>>> n = (1,2,3)
>>> list_literal = list(n)
>>> list_literal
[1, 2, 3]