Android listview 数组适配器答案

【问题标题】：Android list view array adapterAndroid listview 数组适配器
【发布时间】：2016-03-23 08:38:31
【问题描述】：

我正在实现内置的数组列表采用者 uisng“simple_list_item_2”，但出现错误。它说“无法应用来自片段的 getview”，它也无法从 get 解析“get”符号。（位置）

public class AboutFragment extends Fragment {

        ListView listView2;
        String[] items = {"Friendly Map", "Inc"};

        public AboutFragment() {
            // Required empty public constructor
        }


        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container,
                                 Bundle savedInstanceState) {
            // Inflate the layout for this fragment
            View v = inflater.inflate(R.layout.fragment_about, container, false);
            listView2 = (ListView)v.findViewById(R.id.listView2);
            ArrayAdapter arrayAdapter = new ArrayAdapter(getContext(), android.R.layout.simple_list_item_2, items);
            listView2.setAdapter(arrayAdapter);



            return v;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent){

            View view = super.getView(position, convertView, parent);
            String[] entry = listView2.get(position);

            return view;

        }


    }

【问题讨论】：

stackoverflow.com/q/8166497/3790150

标签： android list view

【解决方案1】：

试试这个。

public class AboutFragment extends Fragment {

        ListView listView2;
        String[] items = {"Friendly Map", "Inc"};

        public AboutFragment() {
            // Required empty public constructor
        }


        @Override
        public View onCreateView(LayoutInflater inflater, ViewGroup container,
                                 Bundle savedInstanceState) {
            // Inflate the layout for this fragment
            View v = inflater.inflate(R.layout.fragment_about, container, false);
            listView2 = (ListView) v.findViewById(R.id.listView2);
            ArrayAdapter arrayAdapter = new ArrayAdapter(getContext(), android.R.layout.simple_list_item_2, items);
            listView2.setAdapter(arrayAdapter);



            return v;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent){

            View view = convertView;
            String entry = listView2.get(position);

            return view;

        }


    }

【讨论】：