生成加权重复列表答案

【问题标题】：Generating weighted duplicate lists生成加权重复列表
【发布时间】：2018-04-03 11:17:47
【问题描述】：

我有几个列表如下：

l1=['InitialRequest','Approved','WorkStarted','OnHold','InProgress','OnHold','InProgress','Completed']

l2=['InitialRequest','Approved','WorkStarted','OnHold','OnHold','OnHold','OnHold','Cancelled']

l3=['InitialRequest','Approved','WorkStarted','InProgress','InProgress','InProgress','InProgress','Completed']

...直到 l7。我需要保持列表中给出的顺序，并生成每个列表 15000 次。所以我创建了这些列表的列表：

Status=[l1,l2,l3,l4,l5,l6,l7]

我已经试过了：

Status_b = list(np.random.choice(Status, 15000, replace=True, p=[0.1,0.02,0.5,0.08,0.03,0.07,0.1,0.1]))

但我收到以下错误：

Traceback (most recent call last):

 File "<ipython-input-168-d6488b73dd38>", line 1, in <module>
   Status_b = list(np.random.choice(Status, 15000, replace=True, p=[0.1,0.02,0.5,0.08,0.03,0.07,0.1,0.1]))

 File "mtrand.pyx", line 1117, in mtrand.RandomState.choice

ValueError: a must be 1-dimensional

谁能给我一个解决方案？

【问题讨论】：

标签： python list numpy duplicates

【解决方案1】：

与其让random 自己从列表中选择，不如让它自己选择索引：

weights = [0.1,0.02,0.5,0.08,0.03,0.07,0.1,0.1]
status_idx = np.random.choice(len(status), 15000, replace=True, p=weights)
status_b  = [Status[i] for i in status_idx)

【讨论】：