如何根据某些条件迭代python中的列表项？

Question

如果满足某些条件，我正在尝试迭代 python 中的列表项。我在列表中有 5 个字符串，我想考虑第一个元素并检查我的情况。如果只有条件满足，那么我想去第二个元素等等。

mylist = ["1","2","34","44","55",]
for m in mylist:
    pyperclip.copy(m)
    print(m) # I want to print it every 30 seconds after the condition meets!
    roll = "34"
    if roll == m:
        print(roll) # Now wait for next m from the list!

解释：

假设，我从列表中取出 1，然后复制并打印它。现在在我从列表中打印另一个 m 之前，我必须等待条件。如果 roll 等于 m 则打印卷并等待直到打印下一个 m （即直到那 30 秒）。我想无限做，需要while循环吗？

请随意询问更多解释。

谢谢！

Answer 1

使用while 循环和% 无限次遍历列表

import time
mylist = ["1","2","34","44","55",]
i = 0
l = len(mylist)
while (True):
    m = mylist[i%l]
    # pyperclip.copy(m) # don't know what this is!?
    print(m) 
    roll = "34"
    if roll == m:
        print("printing roll: ",roll)
        time.sleep(30) # waiting 30 secs
    i+=1

1
2
34
printing roll:  34
44
55
1
2
34
printing roll:  34
44
55
1
2
34
printing roll:  34
44
55
1
2
34
........Infinite......

Answer 2

您可以参考下面的代码，只需添加 time.sleep(secs)。 我想无限地做如果循环一个列表，循环到列表的末尾

import time
mylist = ["1","2","34","44","55",]
for m in mylist:
    pyperclip.copy(m)
    print(m) # I want to print it every 30 seconds after the condition meets!
    time.sleep(30)
    roll = "34"
    if roll == m:
        print(roll) # Now wait for next m from the list!