【发布时间】:2020-11-15 22:29:08
【问题描述】:
我正在尝试编写一个使用两个工人的简单 PyQt 小部件。第一个工人(工人 1)立即开始其循环,而第二个工人(工人 2)睡眠 2 秒然后开始。我想得到以下内容:
- Worker 2 暂停 Worker 1 的执行
- Worker 2 启动并完成循环
- Worker 2 完成并让 Worker 1 完成自己的循环。
我试图通过为工人类实现以下代码来实现这一点:
class Worker(QObject):
"""
Create worker class
"""
worker_finished = pyqtSignal()
ask_to_work = pyqtSignal()
glob_lock = QMutex()
def __init__(self, name, sleep_time = 0.5, loops = 10, sleep_at_start=False):
super().__init__()
self._name = name
self.sleep_time = sleep_time
self.loops = loops
self._sleep_at_start = sleep_at_start
self.worker_finished.connect(self.at_finish)
self.ask_to_work.connect(self.pause_execution)
@pyqtSlot()
def run(self):
#This is to make the worker sleep 2 seconds, then ask to run its loop
if self._sleep_at_start:
print("{:s} is sleeping.".format(self._name))
sleep(2)
print("{:s} has awaken.".format(self._name))
self.ask_to_work.emit()
#This acquires the lock and starts the worker loop
self.glob_lock.lock()
print("Lock acquired by {:s}".format(self._name))
for ii in range(self.loops):
print("I am {:s} and I am at step {:d}".format(self._name, ii))
sleep(self.sleep_time)
self.worker_finished.emit()
#Function to attempt the interruption of the worker loop
@pyqtSlot()
def pause_execution(self):
try:
print("Request lock")
self.glob_lock.unlock()
print("Request succeded")
except:
print("No lock to release")
@pyqtSlot()
def at_finish(self):
try:
self.glob_lock.unlock()
print("Successfully released lock at finish.")
except:
print("Releasing the lock at finish went wrong.")
虽然小部件和执行是:
class MainApp(QWidget):
"""
Make the widget
"""
def __init__(self):
super().__init__()
#Set the widget layout
layout = QHBoxLayout(self)
self.button_run = QPushButton("Run workers")
layout.addWidget(self.button_run)
self._threads = []
self._workers = []
#Initialize the workers
worker = Worker("Worker 1", loops=10)
self._workers.append(worker)
worker = Worker("Worker 2", sleep_time=1,
loops=1, sleep_at_start=True)
self._workers.append(worker)
#Connect workers' run methods to the widget button and put the workers into separate threads
self.activate_and_connect_workers()
def activate_and_connect_workers(self):
for worker in self._workers:
self.button_run.clicked.connect(worker.run)
a_thread = QThread()
self._threads.append(a_thread)
worker.moveToThread(a_thread)
a_thread.start()
if __name__ == '__main__':
app = QApplication(sys.argv)
window = MainApp()
window.show()
sys.exit(app.exec_())
我想在终端看到的是:
Lock acquired by Worker 1
Worker 2 is sleeping
I am Worker 1 and I am at step 0
I am Worker 1 and I am at step 1
#...Some lines of Worker 1
Worker 2 has awaken.
Request lock
Request succeded
Lock acquired by Worker 2
I am Worker 2 and I am at step 0
#...Some lines of Worker 2
Worker 2 uccessfully released lock at finish.
Lock acquired by Worker 1
#...More lines of Worker 1
Worker 1 uccessfully released lock at finish.
这不会发生,因为 Worker 2 发出信号以“对自己”释放锁,并且无法将其发送给 Worker 1。这意味着两个进程不同步。最重要的是,程序在 Worker 1 循环结束时崩溃(可能是因为在 Worker 1 重新启动时锁已经释放)。
我应该怎么做才能使代码以所需的方式工作?
【问题讨论】:
标签: python multithreading pyqt signals mutex