退出powershell脚本

Question

我有这个 powershell 脚本，当在某个目录中创建文件时会触发一些指令。 一切正常，但在操作完成后我无法关闭 powershell。 我该怎么做？

### SET FOLDER TO WATCH + FILES TO WATCH + SUBFOLDERS YES/NO
$watcher = New-Object System.IO.FileSystemWatcher
$watcher.Path = "C:\Users\Autostrade\CartellaSFTP"
$watcher.Filter = "*.*"
$watcher.IncludeSubdirectories = $false
$watcher.EnableRaisingEvents = $true  
$uscita = 0

### DEFINE ACTIONS AFTER AN EVENT IS DETECTED
$action = { $path = $Event.SourceEventArgs.FullPath
            $changeType = $Event.SourceEventArgs.ChangeType
            $logline = "$(Get-Date), $changeType, $path"
            Add-content "C:\Users\Autostrade\PHP Script Dati Telepass\log.txt" -value $logline
            # Set up references to executable and script
            $PhpExe  = "C:\PHP\php.exe"
            $PhpFile = "C:\Users\Autostrade\PHP Script Dati Telepass\script.php"

            # Create arguments from Script location
            # usually php.exe is invoked from console like: 
            # php.exe -f "C:\path\myscript.php"
            #$PhpArgs = '-f "{0}"' -f $PhpFile

            # Invoke, using the call operator
            $PhpOutput = & $PhpExe $PhpFile
            PhpOutput
            $uscita = 1
          }    
### DECIDE WHICH EVENTS SHOULD BE WATCHED 
Register-ObjectEvent $watcher "Created" -Action $action
#Register-ObjectEvent $watcher "Changed" -Action $action
#Register-ObjectEvent $watcher "Deleted" -Action $action
#Register-ObjectEvent $watcher "Renamed" -Action $action
while (!$uscita) {sleep 5}
exit

我尝试使用“$uscita”变量来停止 while 并退出，但它不起作用。我还尝试将退出命令放在操作的末尾，但这也不起作用

Answer 1

我以这种方式编辑了代码的最后一部分，现在它可以工作了。所以在动作之后，脚本会自行结束。 代码如下：

while (!$uscita) {
if($? -eq $false) {
    exit
    }
sleep 5}

Answer 2

看起来你的倒数第二行 while 可能返回 true，所以它只是位于 sleep 命令中。

试试这个测试，如果最后一个命令成功完成，它会返回true。

while (!$uscita) {write-output $?; sleep 5}