返回/打印所选文件的路径答案

【问题标题】：Return / Print path of a selected file返回/打印所选文件的路径
【发布时间】：2021-01-14 17:42:34
【问题描述】：

我正在尝试创建一个打开对话框的函数，让用户选择一个文件，然后将其路径作为 std::string 返回。到目前为止我有这个，但我正在尝试获取它，以便它打印并将路径作为字符串返回。

auto GetUserFile() {
    OPENFILENAME ofn;       // common dialog box structure
    char szFile[260];       // buffer for file name 
    HWND hwnd{};              // owner window
    HANDLE hf;              // file handle

    // Initialize OPENFILENAME
    ZeroMemory(&ofn, sizeof(ofn));
    ofn.lStructSize = sizeof(ofn);
    ofn.hwndOwner = hwnd;
    ofn.lpstrFile = (LPWSTR)szFile;
    // Set lpstrFile[0] to '\0' so that GetOpenFileName does not 
    // use the contents of szFile to initialize itself.
    ofn.lpstrFile[0] = '\0';
    ofn.nMaxFile = sizeof(szFile);
    ofn.lpstrFilter = L"All\0*.*\0Text\0*.TXT\0"; // I think this sets the file types that can be selected
    ofn.nFilterIndex = 1;
    ofn.lpstrFileTitle = NULL;
    ofn.nMaxFileTitle = 0;
    ofn.lpstrInitialDir = NULL;
    ofn.Flags = OFN_PATHMUSTEXIST | OFN_FILEMUSTEXIST;

    // Display the Open dialog box. 

    if (GetOpenFileName(&ofn) == TRUE) {
        hf = CreateFile(ofn.lpstrFile, GENERIC_READ, 0,(LPSECURITY_ATTRIBUTES)NULL, OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL,
            (HANDLE)NULL);

        std::cout << ofn.lpstrFile; // ?? prints a bunch of numbers and letters
        // return ofn.lpstrFile; // Want to change this to a string
    }
}

我用于this 的 Windows 文档说 lpstrFile 成员“包含路径和文件名”，但我不确定如何将其实际转换为字符串形式，甚至是我自己可以理解的形式。我可能只是使用了错误的转换方法，我尝试将 lpstrfile 转换为 c 字符串和 std::string，但它们也会给出随机数字或引发访问冲突。

【问题讨论】：

标签： c++ path windows-10

【解决方案1】：

我现在觉得自己像个白痴，但是，不相关的细节，这段代码有效：

#include <iostream>
#include <windows.h>

OPENFILENAME ofn;
DWORD error_value;

using namespace std;

bool openFileDialog(TCHAR szFileName[])
{
    const TCHAR* FilterSpec = "All Files(.)\0*.*\0";
    const TCHAR* Title = "Open";

    const TCHAR* myDir = "C:\\c_plus_plus_trial";

    TCHAR szFileTitle[MAX_PATH] = { '\0' };

    ZeroMemory(&ofn, sizeof(OPENFILENAME));

    *szFileName = 0;

    /* fill in non-variant fields of OPENFILENAME struct. */
    ofn.lStructSize = sizeof(OPENFILENAME);

    ofn.hwndOwner = GetFocus();
    ofn.lpstrFilter = FilterSpec;
    ofn.lpstrCustomFilter = NULL;
    ofn.nMaxCustFilter = 0;
    ofn.nFilterIndex = 0;
    ofn.lpstrFile = szFileName;
    ofn.nMaxFile = MAX_PATH;
    ofn.lpstrInitialDir = myDir; // Initial directory.
    ofn.lpstrFileTitle = szFileTitle;
    ofn.nMaxFileTitle = MAX_PATH;
    ofn.lpstrTitle = Title;
    //ofn.lpstrDefExt = 0; // I've set to null for demonstration
    ofn.Flags = OFN_FILEMUSTEXIST | OFN_PATHMUSTEXIST;

    // false if failed or cancelled
    if (GetOpenFileName(&ofn) == 1)
    {
        cout << "SUCCESS !!! \n";
        return 1;
    }
    else
    {
        cout << "Failure :( \n";
        error_value = CommDlgExtendedError();
        cout << std::hex << error_value;

        return 0;
    }
}

int main()
{
    TCHAR openedFileName[MAX_PATH];

    if (openFileDialog(openedFileName))
        std::cout << "File location\\name: " << openedFileName << "\n";
    else
        std::cout << "User cancelled the operation\n";
}

取自here，它要求对于Visual Studio 2019，字符集设置为“未设置”。

【讨论】：