【发布时间】:2014-11-18 02:34:45
【问题描述】:
我正在使用 jcreator。它表示该过程已完成,但是当您切换到 case 4 然后选择数字 1-9 时,它表示 java.numberformatexception。是什么原因造成的,我该如何解决?我只是这里的初学者。
import javax.swing.JOptionPane;
public class Exer29A {
public static String inputdialog(String s)
{
JOptionPane.showInputDialog(null,s);
return s;
}
static void messagedialog(String r)
{
JOptionPane.showMessageDialog(null, r);
}
public static void main(String[] args) {
int xx, x1, x2;
String n1, n2, LName, MName, FName;
FName = JOptionPane.showInputDialog(null, "What's your first name?");
MName = JOptionPane.showInputDialog(null, "What's your Middle name?");
LName = JOptionPane.showInputDialog(null, "What's your Last name?");
n2 = JOptionPane.showInputDialog(null, "So you are " + FName.substring(0,1).toUpperCase() + FName.substring(1).toLowerCase() + " " + MName.substring(0,1).toUpperCase() + MName.substring(1).toLowerCase() + " " + LName.substring(0,1).toUpperCase() + LName.substring(1).toLowerCase() + " " + "Do you wish to continue?[Y/N]");
if (n2.equalsIgnoreCase("Y"))
{
x1 = Integer.parseInt(JOptionPane.showInputDialog(null, "What do you want to do? \n 1. Add 2 integers \n 2. Area of a rectangle \n 3. Area of a triangle \n 4. Know your fate."));
switch (x1)
{
case 1:
{
x1 = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter 1st integer."));
x2 = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter 2nd integer"));
messagedialog("The sum of two numbers is " + (x1+x2) );
}
break;
case 2:
{
x1 = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter 1st integer."));
x2 = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter 2nd integer"));
messagedialog("The area of the triangle is " + (x1*x2) );
}
break;
case 3:
{
x1 = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter base."));
x2 = Integer.parseInt(JOptionPane.showInputDialog(null, "Enter height"));
messagedialog("The are of the triangle is " + ((double)(0.5*x1*x2)));
}
case 4:
{
xx = Integer.parseInt(inputdialog("Choose numbers 1-9"));
{
if (xx==1)
messagedialog("You will be successful!");
else if (xx==2)
messagedialog("You will have a beautiful life. Blessings would come to you.");
else if (xx==3)
messagedialog("You are handsome/gorgeous. But.....");
else if (xx==4)
messagedialog("You must study well.");
else if (xx==5)
messagedialog("Unfortunately, you are unfortunate.");
else if (xx==6)
messagedialog("You will be an environmentalist. You will be called the Keeper of the Forest.");
else if (xx==7)
messagedialog("You are nothing but luck. You will be poured out with luck.");
else if (xx==8)
messagedialog("8. Nothing but a number. Try again.");
else
messagedialog("Endowed with the gift to serve others, people with the lucky number 9 are able to freely create an easy and relaxed atmosphere. /n Your humanity is welcomed among their friends. Besides, they are brilliant, funny, smart and generous. ");
}
}
break;
default:
messagedialog("invalid");
}
}
else if (n2.equalsIgnoreCase("N"))
System.exit(0);
else
messagedialog("INVALID");
}
}
异常堆栈跟踪:
Exception in thread "main" java.lang.NumberFormatException: For input string: "Choose numbers 1-9"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:580)
at java.lang.Integer.parseInt(Integer.java:615)
at Exer29A.main(Exer29A.java:50)
【问题讨论】:
-
NumberFormatException出现在哪里? -
#3 和#4 之间没有中断,不确定这是不是故意的。您对这种情况有何意见?
-
您的错误实际上是
java.lang.NumberFormatException。必须准确报告错误消息和异常以及所有程序输出。您应该在问题中包含整个堆栈跟踪,而不仅仅是与源代码无关的错误消息的一些错误版本。 -
线程“主”java.lang.NumberFormatException 中的异常:对于输入字符串:java.lang.NumberFormatException.forInputString 中的“选择数字 1-9”(NumberFormatException.java:65)在 java.lang .Integer.parseInt(Integer.java:580) at java.lang.Integer.parseInt(Integer.java:615) at Exer29A.main(Exer29A.java:50)
-
它会询问你的名字然后选择你想做什么然后如果你选择“4”来知道你的命运然后“选择数字1-9”然后该消息就会弹出。它不会在里面输出我的 if else 语句
标签: java swing exception-handling