【发布时间】:2020-04-24 18:59:58
【问题描述】:
如果发生输入不匹配,我想打印 catch 块中的内容。我已经为在此处创建对象的 Marathon 类编写了代码。帮帮我
import java.util.InputMismatchException;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
Marathon m=new Marathon();
System.out.print("Enter name: ");
String name=sc.nextLine();
System.out.print("Enter age: ");
int age=sc.nextInt();
System.out.print("Enter Gender: ");
char gender=sc.next().charAt(0);
System.out.print("Enter Contact no: ");
long number=sc.nextLong();
try{
m.setName(name);
m.setAge(age);
m.setGender(gender);
m.setContactNo(number);
System.out.println("Registered Successfully");
}
catch(InputMismatchException e){
System.out.print("Invalid Input");
}
}
【问题讨论】:
-
您的 try 块在扫描内容之后
标签: java exception error-handling inputmismatchexception