如何在python中禁用堆栈跟踪

Question

我想禁用在引发异常时打印的堆栈跟踪。

Answer 1

每当代码调用logger.exception 方法时，就会自动打印堆栈跟踪。 这是因为.exception方法的exc_info参数的默认值为True。

查看源代码：

def exception(msg, *args, exc_info=True, **kwargs):
    """
    Log a message with severity 'ERROR' on the root logger, with exception
    information. If the logger has no handlers, basicConfig() is called to add
    a console handler with a pre-defined format.
    """
    error(msg, *args, exc_info=exc_info, **kwargs)

为了防止这种情况，您可以像这样将exc_info=False 发送到.exception 方法：

  try:
      raise Exception("Huston we have a problem!")
  except Exception as ex:
      logger.exception(f"Looks like they have a problem: {ex}", exc_info=False)

虽然这似乎可行，但强制用户每次使用该方法时都写exc_info=False 是不好的。因此，为了减轻程序员的负担，您可以修改 .exception 方法，使其像普通的 .error 方法一样运行，如下所示：

# somewhere in the start of your program
# money patch the .exception method
logger.exception = logger.error

  try:
      raise Exception("Huston we have a problem!")
  except Exception as ex:
      logger.exception(f"Looks like they have a problem: {ex}")

Answer 2

环顾四周，我发现了以下解决方案/解决方法：

sys.tracebacklimit = 0