如何在 Windows 上为调用用户获取桌面的绝对路径

Question

如何为启动我的程序的用户获取桌面的绝对路径？

int main () {
  ofstream myfile;
  myfile.open ("C:\\Users\\username\\Desktop\\example.txt");
  myfile << "Writing this to a file" << endl;
  myfile.close();
}

Answer 1

已编辑：正如 Remy Lebeau 建议的那样

我想为每台计算机启动程序获取桌面的绝对路径？

如果您在windows中需要使用API​​ SHGetFolderPath函数，请点击here了解更多信息。

当您获得桌面的路径时，您需要将它与您的文件名组合（附加），生成的路径将代表位于桌面中的文件的完整路径，有完整的代码：

#include <iostream>
#include <Windows.h>
#include <fstream>
#include <shlobj.h> // Needed to use the SHGetFolderPath function.

using namespace std;

bool GetDesktopfilePath(PTCHAR filePath, PTCHAR fileName)
{
    // Get the full path of the desktop :
    if (FAILED(SHGetFolderPath(NULL,
        CSIDL_DESKTOPDIRECTORY | CSIDL_FLAG_CREATE,
        NULL,
        SHGFP_TYPE_CURRENT,
        filePath))) // Store the path of the desktop in filePath.
        return false;

    SIZE_T dsktPathSize = lstrlen(filePath); // Get the size of the desktope path.
    SIZE_T fileNameSize = lstrlen(fileName); // Get the size of the file name.

    // Appending the fileName to the filePath :
    memcpy((filePath + dsktPathSize), fileName, (++fileNameSize * sizeof(WCHAR)));

    return true;
}

int main()
{
    ofstream myFile; 

    TCHAR    filePath[MAX_PATH];             // To store the path of the file.
    TCHAR    fileName[] = L"\\Textfile.txt"; // The file name must begin with "\\".

    GetDesktopfilePath(filePath, fileName);  // Get the full path of the file situated in the desktop.

    myFile.open(filePath);                  // Opening the file from the generated path.
    myFile << "Writing this to a file" << endl;
    myFile.close();

    return 0;
}