命令提示符：dir /s 排除完整路径但包含子文件夹

Question

我有一个简单但烦人的问题。我正在制作一个批处理文件，我正在使用：

dir /B /S /A:-D *.wad *.mdl *.wav *.spr *.bmp *.tga *.pcx *.mp3 *.txt *.res > sample.res

得到：

C:\Downloads\Sample1.wad  
C:\Downloads\Sample2.wav  
C:\Downloads\Folder1\Sample3.mdl  
C:\Downloads\Folder1\Folder2\Sample4.txt  

但我真正想要的是：

Sample1.wad  
Sample2.wav  
Folder1/Sample3.mdl  
Folder1/Folder2/Sample4.txt  

我希望包含子文件夹，但不希望包含完整路径。我怎样才能做到这一点？谢谢。

[编辑：出于我的目的，我显然需要一个 FORWARD 斜杠而不是 BACK 斜杠]

Answer 1

试试这样：

@echo off

setlocal enabledelayedexpansion

(for /f  "delims=" %%a in ('dir /B /S /A:-D *.wad *.mdl *.wav *.spr *.bmp *.tga *.pcx *.mp3 *.txt *.res') do ( 
       set "$Path=%%a"
       set $path=!$path:%cd%=!
       echo !$path:~1!)
)>sample.res

编辑：将\ 替换为/：

@echo off

setlocal enabledelayedexpansion

(for /f  "delims=" %%a in ('dir /B /S /A:-D *.wad *.mdl *.wav *.spr *.bmp *.tga *.pcx *.mp3 *.txt *.res') do ( 
       set "$Path=%%a"
       set $path=!$path:%cd%=!
       set $path=!$path:\=/!
       echo !$path:~1!)
)>sample.res

Answer 2

这对我有用：

FOR /F "tokens=*" %G IN ('dir /B /S /A:-D *.wad *.mdl *.wav *.spr *.bmp *.tga *.pcx *.mp3 *.txt *.res') DO ECHO %~nG%~xG >> sample.res