使用 Windows 命令行删除变量中包含特定字符的文本

Question

我希望删除环境变量中包含等号的文本， 我的代码 sn-p 如下：

SET JAVA_OPTS= -Dlog4j.configuration=./logservice.properties -Duser.timezone=GMT+08:00
SET "logText= -Dlog4j.configuration=./logservice.properties "
SETLOCAL EnableDelayedExpansion
@echo JAVA_OPTS = %JAVA_OPTS%
SET "JAVA_OPTS=!JAVA_OPTS:%logText%= !"
@echo modified JAVA_OPTS = !JAVA_OPTS!
ENDLOCAL & SET "JAVA_OPTS=%JAVA_OPTS%"

文本删除后的预期输出应该是

modified JAVA_OPTS = -Duser.timezone=GMT+08:00

我怎样才能达到预期的效果？

Answer 1

@ECHO OFF
SETLOCAL
SET JAVA_OPTS= -Dlog4j.configuration=./logservice.properties -Duser.timezone=GMT+08:00
SET "logText1= -Dlog4j.configuration"
SET "logText2=./logservice.properties "
SETLOCAL EnableDelayedExpansion
echo JAVA_OPTS = %JAVA_OPTS%
SET "JAVA_OPTS=!JAVA_OPTS:*%logText1%=!"
SET "JAVA_OPTS=!JAVA_OPTS:*%logText2%=!"
echo modified JAVA_OPTS = !JAVA_OPTS!
ENDLOCAL & SET "JAVA_OPTS=%JAVA_OPTS%"
echo final JAVA_OPTS = %JAVA_OPTS%
ENDLOCAL
:: have now backed out environment variable updates - try again
SETLOCAL
SET JAVA_OPTS= -Dlog4j.configuration=./logservice.properties -Duser.timezone=GMT+08:00
SET "logText2=./logservice.properties "
SETLOCAL EnableDelayedExpansion
echo JAVA_OPTS = %JAVA_OPTS%
SET "JAVA_OPTS=!JAVA_OPTS:*%logText2%=!"
echo modified JAVA_OPTS = !JAVA_OPTS!
ENDLOCAL & SET "JAVA_OPTS=%JAVA_OPTS%"
echo final JAVA_OPTS = %JAVA_OPTS%

GOTO :EOF

两种方式。你付钱，你做选择。

问题集中在= 的特殊用途上，cmd 无法区分。替换的是哪个字符串？